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iren2701 [21]
3 years ago
8

Which equation is another way to show 2/3 A. 1/2 ÷ 3 = ___ B. 1/3 ÷ 2 = ___ C. 2 ÷ 1/3 = ___ D. 2 ÷ 3 = ___ E. 3 ÷ 2 = ___​

Mathematics
1 answer:
gulaghasi [49]3 years ago
3 0

Answer:

D

Step-by-step explanation:

A. 1/2 ÷ 3 = 1/6

B. 1/3 ÷ 2 = 1/6

C. 2 ÷ 1/3 = 6/1

D. 2 ÷ 3 = 2/3

E. 3 ÷ 2 = 3/2

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Which of the following situations is best represented by the equation y = 15x ?
IrinaK [193]

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B.) There were 15 more questions on the test than the last test.

Step-by-step explanation:

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HELP! I'm being timed
Rasek [7]

Answer:

X=37

Step-by-step explanation:

Since they are vertical angles they are both equal to 80. Set the other side equal to 80 and solve for X, and you should end up with 37.

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there are 5 green marbles, 4 red marbles, and 3 yellow marbles in a bag. John selects a marble at random, keeps it, and then sel
Daniel [21]

Answer:

1/22

Step-by-step explanation:

  1. 12 total marbles
  2. 5/12 - 1/1 = 4/11
  3. 4/11 - 1/1 = 3/10
  4. 5/12 × 4/11 × 3/10 = 1/22
3 0
2 years ago
3.
natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.

b) In matrix form this is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)

c) The determinant is

\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16

d) Find three determinants:

\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608

\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368

\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304

So,

x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19

e) If the store doubled all prices and inventory, then the new matrix is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)

7 0
3 years ago
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