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MakcuM [25]
4 years ago
8

How do you make 2/5 a percent??

Mathematics
1 answer:
Yakvenalex [24]4 years ago
4 0
Divide 2 by 5.
you get .4
to make a number a percent, you shift the decimal two placed to the right.
so 2/5=.4=40%
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Determine whether the points (–3,–2) and (3,2) are in the solution set of the system of inequalities below. y ≤ ½x + 2 y < –2
lana [24]

Given:

The system of inequalities:

y\leq \dfrac{1}{2}x+2

y

To find:

Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.

Solution:

A point is in the solution set of the given system of inequalities if it satisfies both inequalities.

Check for the point (-3,-2).

-2\leq \dfrac{1}{2}(-3)+2

-2\leq -1.5+2

-2\leq 0.5

This statement is true.

-2

-2

-2

This statement is also true.

Since the point (-3,-2) satisfies both inequalities, therefore (-3,-2) is in the solution set of the given system of inequalities.

Now, check for the point (3,2).

2

2

2

This statement is false because 2>-9.

Since the point (3,2) does not satisfy the second inequality, therefore (3,2) is not in the solution set of the given system of inequalities.

7 0
3 years ago
Find the mean of 81, 97, 99, 89, 91, 76 (round to the hundredths)
Marta_Voda [28]

Answer:

88.83

Step-by-step explanation:

To find the mean of a set of numbers is to find the average a set of numbers.

To solve for the mean you have to add all of the values together and divide that sum by the number of values there are.

Ex. 81, 97, 99, 89, 91, 76

     81 + 97 + 99 + 89 + 91 + 76 = 533

     533 / 6 = 88.83

               ↓

     (number of values)

3 0
3 years ago
Given P(A)=0.31P(A)=0.31, P(B)=0.5P(B)=0.5 and P(A\text{ or }B)=0.535P(A or B)=0.535, find the value of P(A and B) rounding to t
irina [24]

Answer:0.275

Step-by-step explanation:

4 0
3 years ago
What is the division property of exponents?
zavuch27 [327]
<h3>Answer:</h3>

\dfrac{a^b}{a^c}=a^{(b-c)}

<h3>Step-by-step explanation:</h3>

An exponent represents repeated multiplication. For example, ...

... x^3 = x·x·x

... x^2 = x·x

If we divide these, the x's in the denominator cancel an equal number in the numerator:

... (x·x·x)/(x·x) = x

If we represent the repeated multiplication using exponents, we can represent the cancellation by subtraction:

... (x^3)/(x^2) = x^(3-2) = x^1 = x

Once we have this idea in mind that division can be done by subtracting denominator exponents, we can use it regardless of the magnitude or sign of the exponents involved.

7 0
3 years ago
1) Order this list from smallest to largest. 0.3 15% 2 1/2​
ella [17]
I think maybe 0.3 then 2 1/2 and then 15
8 0
2 years ago
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