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-Dominant- [34]
4 years ago
6

Find the value of x. If necessary, round your answer to the nearest tenth. O is the center of the circle. The figure is not draw

n to scale.

Mathematics
1 answer:
g100num [7]4 years ago
5 0

Answer:

The correct answer is first option 15

Step-by-step explanation:

From the figure we can see a circle with center O.

<u>To find the value of x</u>

Here 'x' is the radius of the given circle.

Using the given information we can write,

x² = 12² + 9²

 = 144 + 81

 = 225

x = √225

x = 15

Therefore the correct answer is first option 15

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Step-by-step explanation:

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= 140 - 60 - 12

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3 years ago
Vicky jogged 2 miles in 2 hour. What was her average rate of speed in miles per hour?
Tatiana [17]

Answer:

24

Step-by-step explanation:

because i have done this problem before that is the answer

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3 years ago
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lakkis [162]

Answer:

The given point A (6,13) lies on the equation.  True

The given point  B(21,33) lies on the equation.  True

The given point  C (99, 137) lies on the equation.  True

Step-by-step explanation:

Here, the given equation is : y =\frac{4}{3} x + 5

Now,check the given equation for the given points.

1)  A (6,13)

Substitute x = 6 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (6) + 5  = 4(2) + 5  = 8 + 5 =  13

⇒ y= 13

Hence, the given point A (6,13) lies on the equation.

2)  B  (21,33)

Substitute x = 21 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (21) + 5  = 4(7) + 5  = 28 + 5 =  33

⇒ y  = 33

Hence, the given point  B(21,33) lies on the equation.

3)  C (99, 137)

Substitute x = 99 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (99) + 5  = 4(33) + 5  = 132 + 5 =  137

⇒ y  = 137

Hence, the given point  C (99, 137) lies on the equation.

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3 years ago
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d.  x = 10

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Step-by-step explanation:

I've typed up my workings in MS Word and attached them (as it's very difficult to type this in the Brainly equation editor).

I've used the product, quotient and power log laws.

Product:     log_a(x)+log_a(y)=log_a(xy)

Quotient:    log_a(x)-log_a(y)=log_a(\dfrac{x}{y})

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