<h3>
Answer:</h3>
The molecular formula is C₅H₅OBr
<h3>
Solution and explanation:</h3>
The molar mass of the compound is 161 g/mol
Elements contained in the compound are carbon, hydrogen, bromine, and oxygen.
Atomic masses are;
Oxygen - 16.0 g/mol
Bromine - 79.90 g/mol
Carbon - 12.01 g/mol
Hydrogen - 1.008 g/mol
Assuming the compound contains 1 mole of Bromine and Oxygen
Therefore;
Total mass of bromine and oxygen in the compound= 16.0 g/mol + 79.90 g/mol
If there are x atoms of hydrogen in the compound, then;
Mass of Hydrogen = 1.008 x
Carbon is 12 times the mass of hydrogen, thus
![Mass of Carbon = 12(1.008x)\\= 12.096x](https://tex.z-dn.net/?f=Mass%20of%20Carbon%20%3D%2012%281.008x%29%5C%5C%3D%2012.096x)
Hence;
![161 g/mol = 12.096x + 1.008 x + 16.0 g/mol + 79.90g/mol\\65.1 g/mol = 13.104x\\x = 4.9679\\= 5](https://tex.z-dn.net/?f=161%20g%2Fmol%20%3D%2012.096x%20%2B%201.008%20x%20%2B%2016.0%20g%2Fmol%20%2B%2079.90g%2Fmol%5C%5C65.1%20g%2Fmol%20%20%3D%2013.104x%5C%5Cx%20%3D%204.9679%5C%5C%3D%205)
Therefore;
Hydrogen atoms = 5
Carbon atoms= 5(12.096)/12.01
= 5
Bromine atoms = 1
Oxygen atom = 1
Therefore;
The molecular formula is C₅H₅OBr
Use the Clausius-Clapeyron equation...
<span>Let T1 be the normal boiling point, which will occur at standard pressure (P1), which is 101.3 kPa (aka 760 torr or 1.00 atm). You know the vapour pressure (P2) at a different temperature (T2). And you are given the enthalpy of vaporization. Therefore, we can use the Clausius-Clapeyron equation.
</span>
![ln(P_1/P_2) = \frac{-\delta H_{vap}}{R} \times [\frac{1}{T_1} - \frac{1}{T_2}]](https://tex.z-dn.net/?f=ln%28P_1%2FP_2%29%20%3D%20%5Cfrac%7B-%5Cdelta%20H_%7Bvap%7D%7D%7BR%7D%20%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7BT_1%7D%20-%20%5Cfrac%7B1%7D%7BT_2%7D%5D)
<span>
</span><span>ln(101.3 kPa / 52.7 kPa) = (-29.82 kJ/mol / 8.314x10^{-3} kJ/molK) (1/T - 1/329 K)
</span>
------ some algebra goes here -----
<span>T = 349.99K ...... or ...... 76.8C </span>
Answer:
K = 361.369
Explanation:
C2H4(g) + H2O(g) → CH3CH2OH(g)
∴ ΔG°f(298.15K) CH3CH2OH(g) = - 174.8 KJ/mol
∴ ΔG°f(298.15) C2H4(g) = 68.4 KJ/mol
∴ ΔG°f(298.15) H2O(g) = - 228.6 KJ/mol
⇒ ΔG°f(298.15) = - 174.8 - ( - 228.6 + 68.4 ) = - 14.6 KJ/mol
∴ R = 8.314 E-3 KJ/mol.K
∴ T = 298.15 K
⇒ K = e∧(-(-14.6)/((8.314 E-3)(298.15)))
⇒ K = e∧(5.889)
⇒ K = 361.369
<h3>1. <u>Answer;</u></h3>
Percentage yield = 65.9%
<h3><u>Explanation;</u></h3>
- Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.
Therefore;
- Percentage yield = Actual yield/theoretical yield × 100%
= (1.20 g/1.82 g) × 100%
= 65.9%
<h3 /><h3>2. <u>Answer;</u></h3>
The amount of measured yield over calculated yield
<h3>Explanation;</h3>
- Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.
- The actual yield is the actual amount produced when the experiment or reaction is carried out.
- Theoretical yield is the calculated or expected amount of the product. It is based on the limiting reactant.
<h3>3. <u>Answer</u>;</h3>
= 37.71 g
<h3><u>Explanation;</u></h3>
The balanced equation is:
2 Na + Cl₂ → 2 NaCl.
From the balanced equation:
2.0 moles of Na reacts with 1.0 mole of chlorine gas to give 2.0 moles of NaCl.
- The number of moles of Na = mass/atomic mass),
n = (17.25 g / 22.989 g/mole of Na)
= 0.75 moles
Thus;
- Using cross multiplication and from the equation:
2.0 moles of Na → 2.0 moles of NaCl
0.75 moles of Na → 0.75 moles of NaCl
Therefore;
- The mass of the produced NaCl (m = n x molar mass)
m = (0.75 mole x 58.443 g/mole of NaCl)
= 43.85 g.
- This is the yield if the percentage of yield is 100%, but the percentage yield of the reaction is 86%.
Hence;
The actual yield = (43.85 g) (86/100)
= 37.71 g.
<h3>4. <u>Answer;</u></h3>
Oxygen and hydrogen molecules will mix because of random movement of their molecules.
<h3><u>Explanation;</u></h3>
- Both gasses will diffuse into the other jar until the molecules are well distributed into both containers.
- Diffusion is the movement of molecules from a point of high concentration to areas of low concentration until equilibrium is attained.
- The mixture of gases will have a partial pressure that is equal to the sum of the partial pressures of the component gases.
Answer:
The two chlorine atoms are said to be joined by a covalent bond.
Explanation:
The reason that the two chlorine atoms stick together is that the shared pair of electrons is attracted to the nucleus of both chlorine atoms. Hydrogen atoms only need two electrons in their outer level to reach the noble gas structure of helium.