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Maksim231197 [3]
3 years ago
6

How many grams of H2O is 4.5 x 10 15 molecules? *

Chemistry
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

It is b, 1.3 × 10 ⁻⁷

Explanation:

We know that 1 mol of H₂O is ≈ 18g

We need to get out of molecules and into moles so that we can figure out how many grams of H₂O it would be.

Starting with what we're given, let's set up our equation:

4.5×10¹⁵ molecules × (1 mol / 6.02 × 10²³molecules) × (18gH₂O / 1 mol H₂O) = 1.345 × 10⁻⁷g H₂O

This is kept to 2 significant figures and ∴ 1.3 × 10⁻⁷

Further explanation:

We start out with molecules. We cancel it out using Avagadro's number which is 6.02 × 10²³ = 1 mol. Then, we want to get into grams which means that for 1 mol of H₂O, it is equivalent to 18g using the atomic mass units ( 2(1.008) + 15.999).

Hopefully, this helps you!

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A fixed mass of a gas occupies 1000cm
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the pressure of gas is 100.0 the volume is 500.0

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Type the correct answer in the box. Spell all words correctly. In which system are both energy and matter exchanged with the sur
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open system

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A sample of propane, C3H8, contains 14.6 moles of carbon atoms. How many total moles of atoms does the sample contain
seraphim [82]

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161 atoms

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A sample of propane, C3H8, contains 14.6 moles of carbon atoms. How many total moles of atoms does the sample contain

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4 0
3 years ago
You react 2.43 grams of magnesium with oxygen from the air according to the following reaction. The final mass of the product, m
Leona [35]

Answer:

The mass of oxygen that reacted is approximately 1.6 grams of oxygen

Explanation:

The given information are;

The mass of magnesium in the reaction = 2.43 grams

The final mass of the magnesium oxide = 4.12 grams

The chemical equation for the reaction is given as follows;

2Mg + O₂  →  2MgO

From which we see that two moles of magnesium, Mg, reacts with one mole of oxygen gas molecule, O₂, to produce two moles of magnesium oxide, MgO

The number of moles of magnesium present, n_{Mg}, is given as follows;

n_{Mg} = \dfrac{Mass \ of \, magnesium}{Molar \ mass \ of \, magnesium} = \dfrac{2.43}{24.305} \approx 0.1 \ moles

By the given chemical equation, 2 moles of magnesium reacts with one mole of O₂, therefore;

1 mole of magnesium will react with 1/2  moles of oxygen which is 0.5 moles of oxygen also;

0.1 mole of magnesium will react with 0.05 moles of oxygen

The mass of one mole of oxygen = The molar mass of oxygen = 32 g/mol

The mass of oxygen in the reaction = The number of moles of oxygen × The molar mass of oxygen

The mass of oxygen in the reaction = 0.05 × 32 = 1.6 grams

Also from the molar mass  of MgO which is 40.3044 g/mol, we have;

The mass fraction of oxygen = 16/40.3044 = 0.39698 ≈ 0.4

The mass of oxygen = 0.39698 × 4.12 = 1.636 g

Therefore, the mass of oxygen in the reaction is approximately 1.6 grams.

8 0
3 years ago
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