Answer:
Pure compounds include elements and compounds where a combination of two or more pure substances is a mixture. Only one type of atom comes in the form of a pure element. Multiple atoms consist of a molecule and different atoms consist of a compound. These are all pure substances and individually.
Compound 1: Sodium borohydride
In sodium borohydride (NaBH4), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp3 hybridization in NaBH4, to generate 4 hybrid orbitals. These hybrid orbitals, forms sigma bond with 4 'H' atoms. Due to this, the structure of sodium borohydride in tetrahedral.
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Compound 2: B<span>oron trifluoride
</span>In boron trifluoride (BF3), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp2 hybridization in NaBH4, to generate 3 hybrid orbitals. These hybrid orbitals, forms sigma bond with 3 'H' atoms. Due to this, the structure of <span>boron trifluoride</span> is <span>triangular planner</span>.
A heterogeneous mixture is a mixture that it's components can be easily seen and separated.
c. a jar of mixed nuts
Answer:
see below
Explanation:
1. Heat energy is added to the substance, weakening the electrical attraction between molecules.
2. Both the melting point and boiling point are lower.
3. dipole
4. Water and ethanol have different molecular structures.
5. The lone pairs of electrons in the oxygen atom causes the molecule to be bent; the oxygen atom has a partial negative charge, while the hydrogen atoms have partial positive charges.
[quizlet: captncrun]
Answer : The molecular formula of a compound is, 
Solution : Given,
Mass of C = 64.03 g
Mass of H = 4.48 g
Mass of Cl = 31.49 g
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
Molar mass of Cl = 35.5 g/mole
Step 1 : convert given masses into moles.
Moles of C = 
Moles of H = 
Moles of Cl = 
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = 
For H = 
For Cl = 
The ratio of C : H : Cl = 6 : 5 : 1
The mole ratio of the element is represented by subscripts in empirical formula.
The Empirical formula =
The empirical formula weight = 6(12) + 5(1) + 1(35.5) = 112.5 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
Molecular formula = 
Therefore, the molecular of the compound is,
