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miskamm [114]
3 years ago
5

1/3+2/3 How do you do this

Mathematics
2 answers:
Archy [21]3 years ago
4 0

Answer:

You dont add the denominators since they are the same. You just add the tops. Therefore your answer is 1 or 3/3.

Step-by-step explanation:

VikaD [51]3 years ago
4 0

Answer:

1

Step-by-step explanation:

take the the denominator stays as 3 and you just add 2 and 1 which is 3. 3/3 is the same as 1 whole which is the same as 1. Tell me if you need me to explain this more and I will try my best!

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6x - 2y = 26<br><br> 2x + 3y = 5<br><br> Solve for X and Y
Softa [21]

Answer:

y is equal to -1

x is equal to 4

Step-by-step explanation:

The first thing you would do is multiply the bottom equation by a negative 3. You will get - 6x - 9y = -15. Keep the top equation the same. Both of the 6x's cancel. You then get -11y = 11 so y is equal to negative 1.

Since you have Y, you can now plug that in to any equation to find the value of x. -6x - 2(-1) = 26. You're left with 4. Plug both of the values into each equation to double check.

7 0
3 years ago
A box of national brand cornflakes is $2.09 for 12 ounces. A box of store label cornflakes is $3.09 for 20 ounces.
grin007 [14]

Answer:

A)

  • National brand cornflakes is 0.174 = .17/oz
  • Store label cornflakes is 0.514 = .15/oz

B) The larger box is cheaper per ounce.


C) 2.09 – .30 = 1.79 for 12 ounces. So than $1.79/12= .15/oz.

They  would both be the same so there would be no better deal.


4 0
4 years ago
Help ASAP please!!!!!!!!!
bagirrra123 [75]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Darina [25.2K]

Answer:

Given definite  integral as a limit of Riemann sums is:

\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

4 0
3 years ago
Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel. How old is Daniel now?
Leviafan [203]
Kevin is 6 and Daniel is 3 now (i.e., K is 3 years older than D)
2 years ago K was 4 and D was 1 (i.e., K was 4 times as old as D)
7 0
3 years ago
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