It is not true because there C and E are on different sides, if that makes sense (which means your answer is correct)
Answer:
option 2
Step-by-step explanation:
4^2=16/8=2. 4^2=16/16=1. 2-1=1
identity used is
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
then use
(x+y+z)² = x²+y²+z²+2(xy+yz+xz)
225= 83 + 2(xy+yz+xz)
xy+yz+xz = (225-83)/2
xy+yz+xz= 142/2
xy+yz+xz= 71
ok
now use identity
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
now
x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).
= 15[83 - (71)]
= 15×12
=180
7 + (4^2 + 5) x 2 = 51
(2 + 3) x 3^2 + 39 / 3 = 54
2 x [(4 + 3) x 5 - 6] = 58
[84 / (3 + 4)] x 3 + 1 = 37
Therefore none of them equal 52!
Mutually exclusive events can not occur simultaneously. A light switch can not be both on and off at the same time. A dice can not roll both a 3 and 4 at the same time. A coin can not land on both heads and tail. You can however own both a cat and a dog at the same time.