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KIM [24]
3 years ago
15

Estimate the quotient: 16 3/4 divided by 4 2/3. Show your work.

Mathematics
2 answers:
Alex787 [66]3 years ago
6 0

Answer:

3 33/56

Step-by-step explanation:

16 3/4 convert to fraction: 67/4

4 2/3 convert to fraction: 14/3

67/4  divided by  14/3 = 67(3) / 4(14)

201/56

simplify

3 33/56

Eva8 [605]3 years ago
3 0

Answer:

Step-by-step explanation:

First turn them into improper fractions.

16 3/4 ----> 67/4

4 2/3 -----> 14/3

67/4÷14/3= ?

Now use keep, change, flip strategy

67/4×3/14= 201/56

Now simplify 3 33/56

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You bike for 2 hours at a speed no faster than 17.6 mph. Write an inequality that represents the possible number of miles you bi
Whitepunk [10]
Total no. of hours you spent biking = 2 hours
the speed at which you rode your bike ≤ 17.6 mph
Now,
We have,
speed =  \frac{distance}{time}

17.6 =  \frac{distance}{2}

17.6 *2=  distance

35.2=distance

So, you for given conditions, you can't travel more then 35.3 miles

So, the inequality for the given circumstances is:
x ≤ 35.2 
4 0
3 years ago
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PLZZZZ ANSWER QUICK!!!! A line passes through the points (–1, –5) and (4, 5). The point (a, 1) is also on the line. What is the
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3 years ago
I’m so confused please help I can’t afford another bad grade
iogann1982 [59]

Answer:

2

Step-by-step explanation:

x / (3y)

Let x = 18 and y = 3

18 / ( 3*3)

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8 0
3 years ago
Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th
mihalych1998 [28]

Question:

1. The females worked less than the males, and the female median is close to Q1.

2. There is a high data value that causes the data set to be asymmetrical for the males.

3. There are significant outliers at the high ends of both the males and the females.

4. Both graphs have the required quartiles.

Answer:

The correct option is;

1. The females worked less than  the males, and the female median is close to Q1

Step-by-step explanation:

Based on the given data, we have;

For males

Minimum = 0

Q1 = 1

Median or Q2 = 20

Q3 = 25

Maximum = 50

For females;

Minimum = 0

Q1 = 5

Median or Q2 = 6

Q3 = 10

Maximum = 18

Therefore, the values of data that affect the statistical measures of spread and center are that

The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range

Also the female median is very close to Q1, therefore it affects the definition of a measure of center.

5 0
4 years ago
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
kotegsom [21]

Answer: 68

Step-by-step explanation:

Formula for sample size when prior estimate of population proportion (p) is available:  n=p(1-p)(\dfrac{z^*}{E})^2

, where z*= critical-value.

E= Margin of error.

Let p be the population proportion of  trees are infected with the citrus red mite.

As per given , we have

p=\dfrac{1}{5}=0.2

E= ± 0.08

The critical z-value corresponding to 90% confidence level = z*=1.645

Substitute all the values in the above formula , we get

Required sample size  :n=(0.2)(1-0.2)(\dfrac{(1.645)}{0.08})^2

\Rightarrow\ n=(0.2)(0.8)(20.5625)^2

\Rightarrow\ n=0.16(422.81640625)\\\\\Rightarrow\ n=67.650625\approx68 [Rounded to next integer.]

Thus, the minimum sample size should be taken =68

6 0
3 years ago
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