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3 years ago

14

What does 6 in equal to in millimeters?

1 answer:

finlep [7]3 years ago

6 0

One inch is equal to 25.4 millimeters. So, 6 inches multiplied by 25.4 is equal to 152.4 millimeters.

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Please answer this correctly without making mistakes I want ace expert and genius people to answer this correctly without making

andre [41]

Answer:

it's 36

-4 and 4 cancel out and 6 squared is 36

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3 years ago

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My exam is so hard plz help

nevsk [136]

Answer:

There are four correct expressions.

Step-by-step explanation:

Four correct expressions:

${x}^{2} - x - 42$

${x}^{2} +6x −7x −42$

$x(x−7)+6(x−7)$

$2x +6x-7x−42$

Simplify:

${x}^{2} - x - 42$

$(x+6)(x−7)$

$x(x−7)+6(x−7)$

$2x +6x-7x−42$

${x}^{2} −7x+6x−42$

${x}^{2} - x - 42$

<h3>Hope it is helpful....</h3>

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3 years ago

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steposvetlana [31]

Answer:15 boxes with 4 left over have a great day :)

Step-by-step explanation:

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3 years ago

A car travels at an average speed of 48 miles per hour. How long does it take to travel 180 miles?

Luba_88 [7]

Answer:

3 hours and 45 minutes

Step-by-step explanation:

5 0

4 years ago

The equation a = StartFraction one-half EndFraction left-parenthesis b 1 plus b 1 right-parenthesis.(b1 + b2)h can be used to de

aleksley [76]

Answer:

The equivalent expressions are:

$b1=\frac{2a}{h}-b2$

$h=\frac{2a}{b1+b2}$

Step-by-step explanation:

Given equation for finding area of a trapezoid:

$a=\frac{1}{2}(b1+b2)h\\$

where $a$ represents area, $h$ represents height and $b1\ and\ b2$ represents the base lengths of the trapezoid.

Evaluating $h$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $b1+b2$

$\frac{2a}{b1+b2}=\frac{(b1+b2)h}{b1+b2}$

$\frac{2a}{b1+b2}=h$

$\therefore h=\frac{2a}{b1+b2}$

Evaluating $b1$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $h$

$\frac{2a}{h}=\frac{(b1+b2)h}{h}$

$\frac{2a}{h}=b1+b2$

Subtracting both sides by $b2$

$\frac{2a}{h}-b2=b1+b2-b2$

$\frac{2a}{h}-b2=b1$

$\therefore b1=\frac{2a}{h}-b2$

8 0

3 years ago

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