Evaluate AB for A = 5, B =-2, C = 4 and D = -6.<br> 5/12<br> -5/12<br> -3/2<br> 3/2

The number of hours that a nine month old baby sleeps at night are normally distributed with a population standard deviation of

finlep [7]

Answer:

The margin of error for a confidence interval for the population mean with a 90% confidence level is 0.53 hours.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this quesstion:

$\sigma = 1.5, n = 22$

So

$M = 1.645*\frac{1.5}{\sqrt{22}} = 0.53$

The margin of error for a confidence interval for the population mean with a 90% confidence level is 0.53 hours.

4 0

3 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 30 meters cubed

jekas [21]

Answer:

sorry it's late but the answer should be 20 meters cubed

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Need help ASAP thank you sorry if you can’t see the picture but you can zoom in :) !!!

aleksandrvk [35]

Answer:

264 ft³

Step-by-step explanation:

The following data were obtained from the question:

Pi (π) = 3.14

Height (h) = 21 ft

Radius (r) = 2 ft

Volume (V) =..?

The volume of the cylinder can be obtained as follow:

V = πr²h

V = 3.14 × 2² × 21

V = 3.14 × 4 × 21

V = 264 ft³

Therefore, the of the cylinder is 264 ft³

4 0

3 years ago

Which function is increasing and has a domain of (1, 0);

marin [14]

Answer:

A: f(t) = log(t-1)+2

Step-by-step explanation:

Hopefully this helps!

7 0

3 years ago

1. A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a co

slega [8]

Answer:

a) $83.3\ lb/in^2$

b) $12000\ lb/ft^2$

Step-by-step explanation:

Given : A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a concrete slab.

To find : Determine the stress that the base plate exerts on the concrete slab. Express your answer in units of (a) lb/in². and (b) lb/ft².

Solution :

a) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting ft into inches,

1 feet = 12 inch

2 feet = 2×12= 24 inch

The area of the rectangular base is $A=l\times b$

$A_1=24\times 9$

$A_1=216\ in^2$

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

$S=\frac{W}{A_1}$

$S=\frac{18000\ lb}{216\ in^2}$

$S=83.3\ lb/in^2$

b) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting inches into ft,

1 inch = $\frac{1}{12}\ ft$

9 feet = $\frac{9}{12}=0.75\ ft$

The area of the rectangular base is $A=l\times b$

$A_2=2\times 0.75$

$A_2=1.5\ ft^2$

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

$S=\frac{W}{A_2}$

$S=\frac{18000\ lb}{1.5\ ft^2}$

$S=12000\ lb/ft^2$

5 0

3 years ago

Evaluate AB for A = 5, B =-2, C = 4 and D = -6. 5/12 -5/12 -3/2 3/2