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Vikentia [17]
2 years ago
11

8x-16/x^2-13x+22 please help me I really need it

Mathematics
1 answer:
sasho [114]2 years ago
8 0
The answer is -(5x+16/x^2-22)
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X - 2y = 3<br> 5x + 3y = 2<br> The lines whose equations are shown intersect at which point?
Lady_Fox [76]

The point of intersection of the two lines is at (1,-1)

<h3>System of equation</h3>

The given system of expression is shown below

x - 2y = 3

5x + 3y = 2

The solution to the system of equation is the point of intersection

From equation 1

x = 3 + 2y

Substitute into 2

5(3+2y) + 3y = 2

15 +10y + 3y = 2

13y = -13

y = -1

Substitute y = -1 into 3

x = 3 + 2y

x = 3+(-2)

x = 1

Hence the point of intersection of the two lines is at (1,-1)

Learn more on system of equation here: brainly.com/question/25976025

#SPJ1

8 0
2 years ago
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successi
My name is Ann [436]

Answer:

option C

c. least: $101

greatest: $1001

Step-by-step explanation:

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.

Sum of 10 prizes = 5510

100 is the difference. there is a common difference d=100

So its a arithmetic sequence

the sum formula for arithmetic sequence is

S_n = \frac{n}{2}(2a_1 +(n-1)d)

Sn = 5510, n=10 n d= 100 we need to find out first term a1

5510 = \frac{10}{2}(2a_1 +(10-1)100)

5510 = 5 (2a1 + 900)

5510 = 10a1 + 4500

Subtract 4500 on both sides

1010= 10a1

divide by 10 on both sides

a1 = 101

so first term that is least term is 101

To find out greatest term we use formula

a_n = a_1 + (n-1) d

a(10) = 101 + (10-1)100

= 101 + 900= 1001

greatest is 1001

4 0
3 years ago
Suppose you have some wolves and some dogs. Dogs are named and wolves are not. If you call a dog it will run to you. A wolf woul
Ira Lisetskai [31]

Answer:

4dogs and no wolves

Step-by-step explanation:

when a dog is taken care of (Trained) it could be let to run free in a definite region.

On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.

If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.

But for Wolves from the question it is deduced that:  A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.

With these two, wolves wont be allowed on the plane at all.

8 0
2 years ago
What is the probability that a family of 4 children will have all girls?
Alex73 [517]
Since as of now we're saying that the probability of having a girl is 1/2, we can say:
1/2 * 1/2 * 1/2 * 1/2, because then you're saying a one half chance of having a girl times another one half chance of having a girl, etc.
 That ends up to be 1/16.
3 0
2 years ago
Christie needs 54.3 Square feet of laminate wood suppose each square foot of laminated wood cost $.60 find the amount she has to
Irina18 [472]
It will cost $33.

Since wood cost $ .60 sq ft, you can assume she needs to buy 55 sq ft because she will need to buy enough to have 54.3 square ft.

55 x $ .60 = $33

$32.58 would be he total for the 54.3 sq ft and .42 cents would be for the left over .7 sq ft that she didn’t use
7 0
2 years ago
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