Jan's age is 3 years less than twice tritt's age. The sum of their ages is 30. Find their ages.
2 answers:
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Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:
Solve for x
Subtract 8x from both sides
Add 11 to both sides
Divide both sides by 2
2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
(i) The percentage of students who got high scores in both the subjects English and Mathematics is 46%.
(ii) The total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam exists 138.
<h3>What is probability?</h3>The probability exists in the analysis of the possibilities of happening of an outcome, which exists acquired by the ratio between favorable cases and possible cases.
The number of students who got high scores in Mathematics was 75%.
The number of students who got high scores in English was 65%.
(i) The percentage of students who got high scores in both the subjects
100% - 6% = 94%
(75% + 65%) - 94%
= 140% - 94%
= 46%
Therefore, the percentage of students who got high scores in both the subjects English and Mathematics is 46%.
(ii) The total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam
= 300 46%
= 300 (46 / 100)
= 300 0.46
= 138.
Therefore, the total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam exists 138.
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