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Natasha2012 [34]

3 years ago

6

How do the two interger chip models show that -9-(-4) is the same as -9+4?

1 answer:

natali 33 [55]3 years ago

8 0

Answer:

Two negatives together get a positive

Step-by-step explanation:

-9-(-4)

-(-4)

+4

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Can anyone help with math models?? Please…?

Solnce55 [7]

Answer:

12*1/4= 3

30 is C

16*3/4 = 12

31 is B

8 0

2 years ago

Read 2 more answers

Can someone help me with at least one problem and tell me how you got the answer

Vesna [10]

S=16t^2
if t=3
So you would plug it in
16(3)^2
Then you multipy
16*3^2
=144
It is easier if you use a calculator just type in ti 30 calculator online that should help

4 0

3 years ago

Do I divide or multiply not sure

Makovka662 [10]

Answer:

x=40

Step-by-step explanation:

x= 360-(273+47)

5 0

2 years ago

Which choice is equivalent to the product below when x>0?

V125BC [204]

Answer:

D

Step-by-step explanation:

Using the rule of radicals

$\sqrt{\frac{a}{b} }$ = $\frac{\sqrt{a} }{\sqrt{b} }$

$\sqrt{a\\}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

$\sqrt{\frac{6}{x} }$ × $\sqrt{\frac{x^2}{24} }$

= $\frac{\sqrt{6} }{\sqrt{x} }$ × $\frac{x^2}{24}$

= $\frac{\sqrt{6} }{\sqrt{x} }$ × $\frac{x}{2 \sqrt{6\\} }$

Cancel $\sqrt{6}$ on numerator/ denominator

= $\frac{1}{\sqrt{x} }$ × $\frac{x}{2\\}$

= $\frac{1}{\sqrt{x} }$ × $\frac{(\sqrt{x})^2 }{2}$

Cancel $\sqrt{x}$ on numerator/ denominator, leaving

= $\frac{\sqrt{x} }{2}$ → D

4 0

3 years ago

Which of the following transformations are used when transforming the graph of the parent function...

hram777 [196]

1. 1st transformation is translation the parent function $y=\log_5x$ 6 units to the right to get the function $y=\log_5(x-6).$

2. 2nd transformation is reflection the function $y=\log_5(x-6)$ over the x-axis. This transformation gives you the function $y=-\log_5(x-6).$

3. 3rd transformation is vertical stretch of the function $y=-\log_5(x-6)$ by a factor of 2 to get the function $y=-2\log_5(x-6).$

Only last two are present in options, then

answer: C and D.

5 0

3 years ago