Answer:
acute right acute obtuse obtuse acute
Step-by-step explanation:
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Solve the initial value problem:
dy——— = 2xy², y = 2, when x = – 1. dxSeparate the variables in the equation above:

Integrate both sides:


Take the reciprocal of both sides, and then you have

In order to find the value of
C₁ , just plug in the equation above those known values for
x and
y, then solve it for
C₁:
y = 2, when
x = – 1. So,


Substitute that for
C₁ into (i), and you have

So
y(– 2) is

I hope this helps. =)
Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>
Answer:
Probability is 0.831727
Step-by-step explanation:
The probability can be calculated as below
There are multiple scenarios
Scanerio 1
0 occurance & No damage = 1 - 0.2 - 0.03 - 0.001 = 0.769
Scanerio 2
1 occurance & No damage = 0.2 x ( 1 - 0.7 ) = 0.06
Scanerio 3
2 occurance & No damage = 0.03 x ( 1 - 0.7 )^2 = 0.0027
Scanerio 4
3 occurance & No damage = 0.001 x ( 1 - 0.7 )^3 = 0.000027
P(structure will not suffer any damage) = Scanerio 1 + Scanerio 2 + Scanerio 3 + Scanerio 4 = 0.769 + 0.06 + 0.0027 + 0.000027 = 0.831727
Answer:
10 its just 10 or smthing