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Nady [450]
4 years ago
7

3 square root of 721

Mathematics
1 answer:
NeTakaya4 years ago
5 0

Answer:

La raíz cuadrada de 721  

Step-by-step explanation:

La Segunda Raíz o Raíz Cuadrada del número 721 es 26.8514431642

Esto se comprueba multiplicando 26.8514431642 por si mismo, debe arrojar como resultado 721

o en otro termino 721.9049245737

The Second Root or Square Root of the number 721 is 26.8514431642

This is proven by multiplying 26.8514431642 by itself, it must result in 721

or in another term 721.9049245737

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cupoosta [38]

Answer:

as soon as possible

Step-by-step explanation:

and it an 90 degree angle

u have to add it

5 0
3 years ago
Completely factor the polynomial below.
Blizzard [7]
The first step for solving this expression is to write 6q as a difference.
8q² + 10q - 4q - 5
Now factor out 2q from the first part of the expression (8q² + 10q).
2q × (4q + 5) - 4q - 5
Extract the negative sign from the second part of the expression (-4q - 5).
2q × (4q + 5) - (4q + 5)
Lastly,, factor out 4q + 5 from the expression to find your final answer.
(4q + 5) × (2q - 1) 
This means that the correct answer to your question is (4q + 5) × (2q - 1),, or option D.
Let me know if you have any further questions.
:)
7 0
3 years ago
Need help <br> please solve<br><br> 2 log39
Alexeev081 [22]
You just need a calculator.
The answer is 3.1821

Source: A caluculator
4 0
3 years ago
Help please!<br>a= 2 <br>b= -4<br>c= -3<br>d= 5<br><br>help and explain how to do it pleaseee
slava [35]
(2+-4)--3
(2-4)+3
(-2)+3
1

(-4-2)+-3
(-6)-3
-9
5 0
4 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
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