If A is acute, then all obtuse angles formed are supplementary.
Answer:
odd numbers
Step-by-step explanation:
<em>you can see that end with odd numbers 1 and three so they can best be described as odd numbers</em>
HOPE YOU FIND IT USEFUL
Three lines given -- it's a natural for the cos(theta) law. A small hint: I think the preferred way of doing it is to use the cos(theta) law twice. It will give you a definite answer.
Find G first
g = 6 yd
h = 7 yd
f = 5 yards.
g^2 = h^2 + f^2 - 2*h*f*cos(G)
6^2 = 7^2 + 5^2- 2*7*5*cos(G)
36 = 49 + 25 - 70*Cos(G)
36 = 74 - 70*cos(G)
-48 = - 70 * cos(G) Divide by -70
-38/-70 = cos(G)
0.5429 = cos(G)
cos-1(0.5429) = G
G = 57.12
Now find H
h^2 = g^2 + f^2 - 2*g*f*cos(H)
7^2 = 5^2 + 6^2 - 2*5*6*cos(H)
49 = 25 + 36 - 60cos(H)
49 =61 - 60*cos(H)
Cos(H) = -12 / - 60
Cos(H) = 0.2
H = cos-1(0.2)
H = 78.46
F can be found because every triangle has 180 degrees
F + 78.46 + 57.12 = 180
F + 135.58 = 180
F = 180 - 135.58
F = 44.41
A <<<< Answer.
Answer: 10p+9g
Step-by-step explanation:
2(5p+2g)+5g
10p+4g+5g
10p+9g
Answer:
Dimensions will be
Length = 7.23 cm
Width = 7.23 cm
Height = 9.64 cm
Step-by-step explanation:
A closed box has length = l cm
width of the box = w cm
height of the box = h cm
Volume of the rectangular box = lwh
504 = lwh
Sides which involve length and width and height, cost = 3 cents per cm²
Top and bottom of the box costs = 4 cents per cm²
Cost of the sides 
= 3[2(l + w)h] = 6(l + w)h
= 3[2(l + w)h]
Cost of the top and the bottom 
= 4(2lw) = 8lw
Total cost of the box C = 
+ 8lw
= ![3024[\frac{1}{l}+\frac{1}{w}]](https://tex.z-dn.net/?f=3024%5B%5Cfrac%7B1%7D%7Bl%7D%2B%5Cfrac%7B1%7D%7Bw%7D%5D)
+ 8lw
To minimize the cost of the sides
---------(1)
-------(2)
Now place the value of w from equation (1) to equation (2)
l³ = 378
l = ∛378 = 7.23 cm
From equation (2)
w = 7.23 cm
As lwh = 504 cm³
(7.23)²h = 504
h = 9.64 cm
