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xz_007 [3.2K]
3 years ago
12

Solve the system of equations by substitution

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0
We have y=2x and y=x+2
They both equal y, so substitute the first equation for y in the second equation.
2x=x+2
Let’s get x to one side. Let’s subtract x from both sides.
X=2
Since x=2, just plug in 2 for x.
2+2=4
So,
X=2
Y=4















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Find an expression for the area enclosed by quadrilateral ABCD below.
Helga [31]
  • ∆ABD is right angled hence area:-

\\ \sf\longmapsto \dfrac{1}{2}bh

\\ \sf\longmapsto \dfrac{1}{2}(4x)(3x)

\\ \sf\longmapsto \dfrac{1}{2}(12x^2)

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There is only one option containing 6x^2 i.e Option D.

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Read 2 more answers
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Simplify
denis23 [38]

Hello!

<u><em>Answer: </em></u>

<u><em>1. =-6</em></u>

<u><em>2. =39</em></u>

<u><em>3. =-603</em></u>

_________________________________________________

Explanation: This question's it's about the order of operations. It stands for p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right. (PEMDAS)

1. -4(3-1)+2

Do parenthesis first.

(3-1)=2

-4*2+2

Then do multiply left to right.

-4*2=-8

Add left to right.

-8+2

8-2=6

*Answer should be have negative sign.*

Answer: → \boxed{=-6}

______________________________________________________

2. 3⋅[(30−8)÷2+2]

Do parenthesis first.

(30-8)=22

22/2+2

Then divide left to right.

22/2=11

Add left to right.

11+2=13

Multiply left to right.

3*13=39

*Answer should be have positive sign.*

Answer: → \boxed{=39}

_____________________________________________________

3. 14(1-23)2+13

Do parenthesis first.

(1-23)=-22

14(-22)*2+13

Then, you multiply left to right.

14(-22)=-308

-308*2=-616

Add/subtract left to right.

-616+13

616-13=603

*The answer must be have a negative sign*

Answer: → \boxed{=-603}

____________________________________________________________

Hope this helps!

Thank you!

Have a great day!

-Charlie

7 0
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Draw and lable a pentagon and a quadrilateral
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