Answer:
B is the correct answer. The two median numbers are 88 and 92. If you find the average of those, you get 90. Therefore, the median is 90.
Step-by-step explanation:
I think that the answer is A.
Answer:
z=14.73
p=0.000
for 99% confidence level the null hypothesis is rejected, thus majority of us adults would not bothered if the NSA collected personal records.
Step-by-step explanation:
: Half of US adults would not bothered if the NSA collect records of personal telephone calls
: Majority of the adults would not bothered if the NSA collect records of personal telephone calls
According to the sample, z-value can be found using the formula:
z=
where
- X is the adults, who would not be bothered in the survey (397)
- M is the mean of the distribution of null hypothesis (257)
- n is the sample size (514)
- p is the proportion of the sample, who said they would not bothered (
≈ 0.77)
Putting these numbers in the formula,
z=14.73 and corresponding p value is p≈0.000
Since p<0.01, for 99% confidence level we reject the null hypothesis, thus majority of us adults would not bothered if the NSA collected personal records.
22.5% written as a fraction in simplest form is 9/40 . Hope i helped.
The distributive property:
