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IRISSAK [1]
2 years ago
9

−76 = −0.8k k = What number represents k

Mathematics
1 answer:
Over [174]2 years ago
8 0

Answer:

k= 95

Step-by-step explanation:

-76=-0.8k

-76/-0.8=k

95=k

k= 95

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What expression represents the perimeter of the rectangle?<br> shown below
Komok [63]

Answer:

4x + 4

Step-by-step explanation:

perimeter= breadth + length + breadth + length

(x+2)+(x+2)+x+x

= 4x(because there is 4 x) + 2 +2

= 4x + 4

5 0
3 years ago
Yolanda is planning to put a pool in her backyard. The scaled model below gives the reduced measures for diameter and depth. The
atroni [7]

Answer:

C option: 6 feet

Step-by-step explanation:

Since Yolanda wants to keep the pool in proportion to the model, the ratio of diameter to depth of model and the pool will be same.

Let the depth of pool is x feet.

Ratio of Diameter to Depth of Model = Ratio of Diameter to Depth of pool

This means the depth of pool should be 6 feet if Yolanda wants to keep the pool in proportion to the model.

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4 0
3 years ago
Read 2 more answers
Jorge earns $9,567 a month. Which number is $9,567 rounded to the nearest hundred?
Maksim231197 [3]
To find $9,567 rounded to the nearest hundred you must first find the hundreds place which is where 5 is then according to the number behind it you either round up or you keep 5 the same since the number behind 5 is 6 you round 5 up one which brings 5 to 6 now everything behind your new number is turned to 0. so your new amount would be $9,600
7 0
2 years ago
What is the value of n in the equation 3n + 2(n + 2) = 9n + 12?
Alex777 [14]
3n+2n+4=9n+12
5n+4=9n+12
4-12=9n-5n
-8=4n
Divide both sides by 4
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6 0
2 years ago
Please help this question.
sergejj [24]

Answer:

a). 59.049°C

b). 2.1179 seconds

Step-by-step explanation:

Expression representing the final temperature after decrease in temperature of the metal from 100°C to T°C is,

T = 100(0.9)^{x}

where x = duration of cooling

a). Temperature when x = 5 seconds

T = 100(0.9)⁵

  = 59.049

  ≈ 59.049°C

b). If the temperature of the metal decreases from 100°C to 80°C

Which means for T = 80°C we have to calculate the duration of cooling 'x' seconds

80 = 100(0.9)^{x}

0.8 = (0.9)^{x}

By taking log on both the sides

log(0.8) =log[(0.9)^{x}]

-0.09691 = x[log(0.9)]

-0.09691 = -0.045757x

x = \frac{0.09691}{0.045757}

x = 2.1179

x ≈ 2.1179 seconds

3 0
3 years ago
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