Step-by-step explanation:
i)=
m=2/3
x=-3
y = 5
now
y=mx+c
or, 5 = 2/3× -3 + c
or, 5 = -2+c
c =7
now,
y= mx + c
or, y = 2/3×x+7
or, y = 2x/3+7
or, 3y = 2x+21
so, 3y-2x=21
equation would be 3y-2x=21.
now
ii)=
if slope of 3y-2x=21 and 2x-3y = 0 are same, they are parallel.
2x-3y = 0
2x = 3y
lets suppose x is 9
now
2x=3y
2×9 = 3y
or, 18 = 3y
so, y = 6
one coordinate would be (9,6) now
lets again suppose x is 3
2x=3y
2×3 = 3y
or, 6 = 3y
so, y = 2
another coordinate is (3,2)
now lets find slope
x1=9,y1=6
x2=3,y2=2
slope = (y2-y1)/(x2-x1)
= (2-6)/(3-9)
= -4/-6
= 2/3
Since, slope of 3y-2x=21 and 2x-3y has same slope 2/3, they are parallel.
Answer:
<h3>#4</h3>
It includes all the points between those endpoints.
<h3>#5</h3>
Intersection of the planes results in line.
<h3>#6</h3>
An axiom is a statement that is so evident or well-established, that it is accepted without controversy or question
Slope of tangent line = dy/dx = 2x+3
k is y_intercept of tangent line
2x+3 = -1
x = -2
y = (-2)^2+3(-2)+1 = -1
tangent line passes through point (-2,-1)
k = x+y
k = -2 -1
k = -3
Answer:
hi
Step-by-step explanation:
Answer
Slope between two given points (1,3) and (2,7) is
m=
2−1
7−3
=4
Then perpendicular slope is m
1
=
4
−1
The line equation with this slope is given by
y=
4
−1
x+c.......(1)
Now, the above line passes through the point (−4,−3)
⇒−3=
4
−1
×(−4)+c
⇒c=−4
Therefore required line is 4y+x+16=0 (Substitute
′
c
′
in (1) and simplify)
A domain is a set of all first elements of ordered pairs (x-coordinates) The range is the set of second elements of ordered pairs (Y-coordinates) Domain and range can be seen clearly on the graphic
