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olasank [31]
2 years ago
11

What is a common mistake when evaluating and documenting skill sets

Mathematics
2 answers:
diamong [38]2 years ago
7 0

Answer:

confusing activities with accomplishments.

Step-by-step explanation:

MissTica2 years ago
6 0

Answer:

confusing activities with accomplishments

Step-by-step explanation:

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10 points!!HELPP ME PLEASE ❗️❗️4. Figure HJKL - Figure PQRS
umka21 [38]

Answer:

B I think b djdjdjdjddhjssj

7 0
2 years ago
Simplify: x^5. X-^5?
WARRIOR [948]

Answer:

i believe the answer you are looking for is 1?

Step-by-step explanation:

7 0
3 years ago
After a storm, two street lights with the same length are leaning against each
Ray Of Light [21]

Answer:

c = 4.79 feet

Step-by-step explanation:

Given question is incomplete without a picture; find the question with the attachment.

Two poles AD and DB of same length are leaning against each other.

Distance between the poles (AB) = 45 feet

m(∠ADB) = 180°- (60 + 50)°

               = 70°

By sine rule,

\frac{sin50}{AD}=\frac{sin70}{45}=\frac{sin60}{DB}

AD=\frac{45\times (sin50)}{sin70}

      = 36.68 ft

Similarly,

DB = \frac{45\times sin60}{sin70}

     = 41.47 ft

Now c = DB - AD

           = 41.47 - 36.68

           = 4.79 feet

4 0
3 years ago
Is 26 a perfect square explain
Nataly_w [17]
No because there is not a number that is the same number that equals to 26
5 0
3 years ago
A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is
ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

7 0
3 years ago
Read 2 more answers
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