If you divide X which is 5 by 5, then you will get 1.
5^1 will be 5.
5 divided by 0 does not have a solution. It is not a number.
It is possible to subtract an integer with a negative sign from another number, for example 5-(-3). Multiplying two negative signs will make the sign positive, so the problem would then be this: 5+3. That equals 8.
1+1-1x1/1= 1
st + 3t = 6 for s
Subtract 3t to both sides
st + 3t - 3t = 6 - 3t
Simplify
st = 6 - 3t
Divide both sides by t
st/t = (6-3t)/3
simplify
s = 6/3 - 3t/3
s = 2 - t
There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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Answer:
$367.50 and y=0.3x+300
30% of 225 is 67.50 and her guaranteed salary is 300 so 300+67.50=$367.50.
Answer:
The answer is "Option C".
Step-by-step explanation:
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