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Pavel [41]
3 years ago
8

A pair of consecutive integers has the property that 8 times the lesser is more than 4 times the greater. Find the least pair of

integers with this property.
Mathematics
1 answer:
daser333 [38]3 years ago
5 0
2 and 3
negative numbers won't work, nor will 0
1 and 2 won't work because 1*8=2*4
2 and 3 is the answer
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WRITING TO EXPLAIN, HOW COULD YOU USE 5 X 6 =30 TO FIND THE PRODUCT <br> OF 6 X6 ?
Solnce55 [7]
5x6=30
6x6=36

You would need 1 more 6
I can't explain this very well, sorry.
8 0
3 years ago
Read 2 more answers
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
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Margarita [4]

Answer:

Ok

Step-by-step explanation:

do u mean into bracket 61/4 raised to the power of 4???

7 0
3 years ago
Please help me with this word problem
Serhud [2]

Answer:

21 1/3 inches

Step-by-step explanation:

Inverse variation means that when the frequency goes up by a factor of 576/256 = 9/4, the length of the string goes down by a factor that is the inverse of that, 4/9.

4/9·48 inches = 21 1/3 inches

4 0
3 years ago
LCM of 16, 28, and 56
Sindrei [870]

Answer:

2

Step-by-step explanation:

2x8=16, 2x14=28, and 2x28=56

6 0
3 years ago
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