Answer:
<em>y = x ÷ 2</em>
Step-by-step explanation:
We are given a table of values, which will be represented as ordered pairs (x,y) below:
(2,1) (4,2) (8,4) (10,5) (16,8)
We are required to select one of the functions that match the numeric relationship between x and y.
We could test them one by one, but at simple observation, we can note the values of y are half of the values of x:
2/2=1
4/2=2
And so on. Thus the only function that divides the value of x by 2 to find the value of y is:
y = x ÷ 2
Answer:
17 hours
take $192 and divide it by 12 so you know how much they make per hour
$192 / 12 = 16
then you're going to take $272 and divide it by what you know now - how much they make per hour (this will get you how many hours they worked)
$272 / 16 = 17
Answer:
y=35x+50
35*8=280
280+50=330
yes there will be 10 dollars left
I hope this is good enough:
First find the common denominator
5/8=25/40
2/5=16/40
3/4=30/40
Next you can cross multiply
25/40=x/10 pounds
16/40=x/10 pounds
30/40=x/10 pounds
First
25(10)/40= 6.25 pounds
16(10)/40= 4pounds
30(10)/40= 7.5 pounds
These are the amounts that were left in the bag
10-6.25=3.75
10-4=6
10-7.5=2.5
3.75+6+2.5= 12.25
All together they put 12.25 pounds of soil in the flower bed
Hey there!
In order to find if a fraction would result in a repeating decimal, recall that a fraction is a division problem written vertically. All that you have to do is divide the numerator by the denominator. Also, remember that a repeating decimal will result in the same number after the decimal point as long as the calculator can handle.
3 ÷ 4 = 0.75
1 ÷ 9 = 0.11111111...
5 ÷ 11 = 0.45454545...
3 ÷ 0.42857143...
As you can see, two out of your four answer choices give you a repeating decimal. B gives you a repeated number of "1" while C gives you "45". D doesn't count since there is no pattern of repeated numbers that it follows.
Both B and C fall into the category of repeating decimal. If you're only able to choose one answer, I would ask your teacher, a parent, or a peer what they think.
Hope this helped you out! :-)
