(-6y-2)+5(3+2.5y) expend
-6y-2+15+12.5
6.5y+13
Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
Answer:
9) 1/48
11) 1/24
13) 5/16
14) 1/8
Step-by-step explanation:
9) P(A and 5) = 1/8 × 1/6
11) P(J and LT 3) = 1/8 x 2/6
13) P (consonant and odd) = 5/8 x 1/2
14) P ('M' or 'T' and GT 3) = [(1/8+1/8) × 1/2] = 2/8 x 1/2
Answer:
C
Step-by-step explanation:
x^2 + (x+3)^2 = 117
x^2 + x^2+6x+9 =117
2x^2 + 6x - 108 = 0
(2x-12)(x+9)=0
x=-9,6
x cannot be negative therefore, x = 6
Answer:
d a m i dont even know this
Step-by-step explanation:
