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2 years ago

What is the common denominator of 1/9 and 5/12

Mathematics

1 answer:

Delicious77 [7]2 years ago

3 0

I think it 36 (hopefully)

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Eduardwww [97]

Do you have a question about it ?

5 0

2 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the instanteous rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at exactly t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

2 years ago

At a football stadium, 4% of the fans in attendance were teenagers. If there were 120 teenagers at the football stadium, what wa

Law Incorporation [45]

1200 divided by 4%= 3000

3 0

2 years ago

Consider the enlargement of the rectangle.

Drupady [299]

Answer:

2.5

Step-by-step explanation:

i did it and got it right

3 0

2 years ago

Read 2 more answers

Simplify (4^3)^5 - - - - -

MissTica

Answer:

$\large\boxed{(4^3)^5=4^{15}}$

Step-by-step explanation:

$\text{Use}\ (a^n)^m=a^{nm}\\\\(4^3)^5=4^{(3)(5)}=4^{15}$

6 0

2 years ago

Read 2 more answers