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Mrrafil [7]
3 years ago
11

The hanging mass is released and allowed to fall. When it has traveled a distance h (that is, the moment just before it hits the

floor), what type(s) of energy is/are present in the system
Physics
1 answer:
abruzzese [7]3 years ago
5 0

Answer:

Gravitational potential energy to kinetic energy

Explanation:

In this case you have a case about conservation of energy.

When the mass is released and allowed to fall, its energy is completely gravitational potential energy with a value of U = mgh. m is the mass, g is the gravitational constant and h is the height to the floor from the mass.

While the mass is falling down part of its potential energy converts to kinetic energy of value K=1/2mv^2, because the mass has been acquiring more and more velocity.

Thus, the kinetic energy is increasing while the potential energy is decreasing.

When the mass is just above the floor (the moment just before the mass hits the floor) all its potential energy has been converted to kinetic energy.

Then, you have that the kinetic energy of the mass when the mass is just above the floor, is equal to the potential energy when the mass is at height of h. That is:

mgh=\frac{1}{2}mv^2

This is how the law of conservation of energy is fulfilled.

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Answer:

A nuclear winter is a climatic phenomenon that would follow the detonation of several atomic bombs in the event that a nuclear war broke out. These bombs would cause firestorms that would raise smoke, dust and particles into the atmosphere that would end up in the stratosphere and eventually spread throughout the globe.

Explanation:

That idea is far fetched, because even though those same particles would absorb sunlight, it would raise the temperature in the stratosphere and cause a decrease in temperature in the Earth's layer. Unable to seep the sun's rays, many plant species would die and this would affect the entire food chain.

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6 0
3 years ago
A laser emits light of frequency 4.74 x 1014 hz. what is the wavelength of the light in nm?
Ulleksa [173]
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3 years ago
Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. T
raketka [301]

Answer:

ΔL =0. 000312  m

Explanation:

Given that

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So the length at  13.0 ∘C above room temperature

L=1+2.4\times 10^{-5}T

L=1+2.4\times 10^{-5}\times 13

L=1.000312 m

So the change in length

ΔL = 1.000312 - 1.0000 m

ΔL =0. 000312  m

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Explanation:

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