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jok3333 [9.3K]
3 years ago
7

The hair dryer has a plastic case so there is no need for an earth wire connection in the plug ,explain why the hair dryer is st

ill safe to use.
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

plastics are unable to conduct electricity and heat due to there being no free flowing electrons, meaning they are safe to use.

Explanation:

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Because of your success in physics class you are selected for an internship at a prestigious bicycle company in its research and
tiny-mole [99]

To develop the problem it is necessary to apply the equations related to the moment of inertia.

The given values can be defined as,

M = 1.0 kg

r = 0.5 m

m = 10 g

I = 0.280 kg.m^2

According to the definition of the moment of inertia applied to the exercise we can arrive at the equation that,

I = I_{rim} + n * I_{spoke}

Where n is the number of spokes necessary to construct the wheel.

I_{rim} = M*r^2 = 1.0 * 0.5^2

I_{spoke} = \frac{1}{3} * m * r^2 = \frac{1}{3}* 10 * 10^-3 * 0.5^2

Replacing the values at the general equation we have,

0.280 = 1.0 * 0.5^2 + n * (1/3 * 10 * 10^-3 * 0.5^2 )

Solving for n,

n = 36

Therefore the number of spokes necessary to construct the wheel is 36

PART B) The mass of the wheel is given by the sum of all masses and the total spokes, then

M_w= M + n*m

M_w = 1.0 + 36* 10 * 10^{-3} Kg

M_w = 1.36 Kg

Therefore the mass of the wheel must be of 1.36Kg

4 0
4 years ago
Scientists have proven that genes play no role in self-esteem. Please select the best answer from the choices provided. T F
IRINA_888 [86]
The answer is False give thanks for the answer m8 and happy Halloween
6 0
3 years ago
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What material reduces thermal energy
expeople1 [14]

Answer:

Insulation helps to prevent that transfer of heat.

3 0
3 years ago
A mass of 150 g stretches a spring 1.568 cm. If the mass is set in motion from its equilibrium position with a downward velocity
nadezda [96]

Answer:

u(t)=\frac{1}{5} sin\ (25t)

Explanation:

Given:

  • mass of the body stretching the spring, m=150\ g
  • extension in spring, \Delta x=1.568\ cm
  • velocity of oscillation, u'(0)=20\ cm.s^{-1}
  • initial displacement position of equilibrium, u(0)=0

<u>According to given:</u>

m.g=k.\Delta x

150\times 980=k\times 1.568

k=93750\ dyne.cm^{-1}

<u>we know frequency:</u>

\omega=\sqrt{\frac{k}{m} }

\omega=\sqrt{\frac{93750}{150} }

\omega=25

Now, for position of mass in oscillation:

u= A.sin\ (\omega.t)+B.cos\ (\omega.t)

u= A.sin\ (25.t)+B.cos\ (25.t)

at t=0;\ u(0)=0\ \Rightarrow A=0

∴u(t)=B.sin\ (25.t)

∵ at t=0;\ u'(0)=20\ cm.s^{-1}\ \Rightarrow B=\frac{1}{5}

u(t)=\frac{1}{5} sin\ (25t)

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3 years ago
Which object would have the most momentum? A. a 500-pound car moving at 20 miles per hour B. a 200-pound car moving at 60 miles
Julli [10]
I would say B
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