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Anit [1.1K]
3 years ago
12

What is the area of circle with a diameterms of 10 m​

Mathematics
1 answer:
pentagon [3]3 years ago
6 0

Answer:

exact area = 25(pi) m^2

approximate area = 78.54 m^2

Step-by-step explanation:

diameter = 10 m

radius = diameter/2 = 10 m / 2 = 5 m

area = (pi)r^2

area = (pi)(5 m)^2

area = 25(pi) m^2

area = 78.54 m^2

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Answer:

b(a) =\frac{a}{7} -5

Step-by-step explanation:

Given

A(b) = 14 * \frac{b + 5}{2}

Required

Determine the inverse function b(a)

Write A(b) as a

a = 14 * \frac{b + 5}{2}

Swap a and b

b = 14 * \frac{a + 5}{2}

b = 7(a + 5)

Divide both sides by 7

a + 5 = \frac{b}{7}

Maka a the subject

a =\frac{b}{7} -5

Swap a and b again

b =\frac{a}{7} -5

Hence:

b(a) =\frac{a}{7} -5

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3 years ago
Simplify 2(x + 6) - 8
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Answer:

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Step-by-step explanation:

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Mnenie [13.5K]

Step-by-step explanation:

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3 years ago
One end of a line segment has the coordinates (-6,2). If
CaHeK987 [17]

Answer:

The coordinates of the other end is (16,2)

Step-by-step explanation:

Given

End 1: (-6,2)

Midpoint: (5,2)

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})

So

x = \frac{x_1 + x_2}{2} and y = \frac{y_1 + y_2}{2}

Where (x_1,y_1) = (-6,2) and (x,y) = (5,2)

So, we're solving for (x_2,y_2)

Solving for x_2

x = \frac{x_1 + x_2}{2}

Substitute 5 for x and -6 for x₁

5 = \frac{-6 + x_2}{2}

Multiply both sides by 2

2 * 5 = \frac{-6 + x_2}{2} * 2

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Add 6 to both sides

6 + 10 = -6 +6 +  x_2

x_2 = 16

Solving for y_2

y = \frac{y_1 + y_2}{2}

Substitute 2 for y and 2 for y₁

2 = \frac{2 + y_2}{2}

Multiply both sides by 2

2 * 2 = \frac{2 + y_2}{2} * 2

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Subtract 2 from both sides

4 - 2 = 2 - 2 + y_2

y_2 = 2

(x_2,y_2) = (16,2)

Hence, the coordinates of the other end is (16,2)

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