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beks73 [17]
3 years ago
6

Write an equation in slope-intercept form for the line with slope -4 and y-intercept 6 . Then graph the line.

Mathematics
1 answer:
WITCHER [35]3 years ago
3 0

Answer:

(-4,6)

Step-by-step explanation:

graph in second quadrant

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What is the slope between the points (3, 5) and (-2, -4)
Tamiku [17]
The slope is 9/5! hope this helps!!
6 0
3 years ago
Suppose you always eat a particular brand of cookies out of the standard sized package it comes in from the store. You notice th
Blababa [14]

Answer:

There are 91 cookies in the package of cookies

Step-by-step explanation:

The given parameter for the number of cookies are;

The number of cookies left when eating 3 at a time = 1 cookie

The number of cookies left when eating 5 at a time = 1 cookie

The number of cookies left when eating 7 cookies at a time = No cookie leftover

Let 'n' represent the number of cookies in the pack, let 'a', 'b', and 'c' be the multiples of 3s, 5s, and 7s in 'n', respectively, we have;

The number of cookies in the pack, n < 100

Therefore, we have;

3·a = n - 1

5·b = n - 1

7·c = n

∴ n - 1 is a multiples of 3 and 5 less than 100 which are;

15, 30, 45, 60, 75, and 90

Therefore, the possible values of 'n' are'

n = n - 1 + 1 = 15 + 1 = 16, 30 + 1 = 31, 45 + 1 = 46, 60 + 1 = 61, 75 + 1 = 75, 90 + 1 = 91

Multiples of 7 includes;

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, and 98

Therefore, n = 91 which is the number that appear simultaneously in both search

The number of cookies in a package = 91 cookies

3 0
3 years ago
There are 10 boys trying out for the track team. Truman and Ryan are the two fastest runners. If the coach randomly picks two bo
vichka [17]
10 kids total

picking Truman would be 1 out of 10 or 1/10

then there would be 9 kids left so picking Ryan would be 1 out of 9 or 1/9

the probability of picking both would be 1/10 * 1/9 = 1/90
5 0
4 years ago
Use the Order of Operations to evaluate this expression
Doss [256]
Unfortunately, I don’t knooow :(
5 0
3 years ago
In a hospital there are 56 TB patients. The patients are grouped with respect to their ages.
zalisa [80]
<span>Table:

Class Boundaries         Frequency

5-10                              8

10-15                            9

15-20                          15

20-25                          10

25-30                           8

30-35                           6
                                ----------
total                           56

Average =

[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
---------------------------------------------------------------------------------------------------
</span>                                                      56

That is 1075 / 56 = 19.2

Answer: 19

5 0
4 years ago
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