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Soloha48 [4]
3 years ago
15

Solve the system of equations

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

Step-by-step explanation:

-4x + 2y = -30

-2x + 2y = -10

-4x + 2y = -30

 2x - 2y = 10

-2x = -20

x = 10

-2(10) + 2y = -10

-20 + 2y = -10

2y = 10

y = 5

(10, 5)

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Write the equation for a line in Slope-Intercept Form (y = mx +b) given the two points below (2,10) (3,-5)
kicyunya [14]

Given:

The two end points of a line are (2,10) and (3,-5).

To find:

The equation of the line in the slope intercept form.

Solution:

The slope intercept form of a line is

y=mx+b

Where, m is slope and b is the y-intercept.

The two end points of a line are (2,10) and (3,-5). So, the equation of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-10=\dfrac{-5-10}{3-2}(x-2)

y-10=\dfrac{-15}{1}(x-2)

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On further simplification, we get

y-10=-15x+30

y=-15x+30+10

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Therefore, the slope intercept form of the given line is y=-15x+40.

8 0
3 years ago
-12=3+3u Solve for “u”
Kipish [7]

Answer:

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6 0
3 years ago
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Answer:

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Answer:

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3 years ago
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