We know that the law of sines states that:

For simplicity, let:

In triangle A1BC this leads to:

Therefore:

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:
The third one should be correct, “IMO” if the second person that answers agrees it’s 100%, I’ve had a question similar but I’m not sure exactly.. sorry tho, please lmk if somethings wrong “I will reply I’m not like those kids trying to get coins”
Answer:
Neither i think
Step-by-step explanation:
Answer:
90 in²
Step-by-step explanation:
First,check the figure I provided .
Area of the figure = area1 + area2 + area3 + area4
= (3×2) + (7×7) + (7×2) + (7×6)÷2
= 6 + 49 + 14 + 21
= 90
10% = 6
25% = 15
50% = 30
20% = 12