20 = 2 x 2 x 5
15 = 3 x 5
common divisor (CD) of 20 and 15 is 5 so n should be 5 and each group has 4 boys and 3 girls.
If there are more than one CD, then there are more than one answer.
If they ask for the largest number of groups, greatest common divisor (GCD) will be the answer.
The cost of a senior citizen ticket is $15 and the cost of a student ticket is $12.
How did I get this?
We know that 6 citizen tickets and 7 student stickers sold for $174 the first day. And 10 citizen tickets and 14 student tickets sold for $318 the second day.
1. create two equations out of this: C= citizen cost per ticket and S = student cost per ticket.
6C + 7S = $174
10C + 14S = $318
2. Use process of elimination. Multiply the first equation by 2 because we want two variables to cancel out.
-12C - 14S = -$348
10C + 14S = $318
Combine like terms.
-2C = $30
Divide by -2 on both sides. The left side cancels out.
C = $30/-2
C = -$15 (In this case the negative doesn't matter)
C = $15 (cost of senior citizen ticket)
Plug the value of C into any of the two equations so we can get the value of S.
6($15) + 7S = $174
Distribute the 6 into the parenthesis.
$90 + 7S = $174
Subtract both sides by $90 and the left side will cancel out.
7S = $84
Divide both sides by 7.
S = $12
Student ticket: $12
Senior citizen ticket: $15
Answer:
Step-by-step explanation:
This function I believe has one x intercept which is (-2/13,0)
<span> 4 • (3j - 4) - 9
</span><span> 12j - 25</span>
What can be used on this is the distance over time formula, so what you,do is divide 228 by 4 to get the distance traveled in one hour. And 288/4=57. So they traveled 57 mi in one hour. Hope this helped.
