(1)Plastics (i.e. synthetic polymers) are used frequently for many applications because they tend to be (a) easy to fabricate items with, by moulding, or other methods, (b) can be strong even though very lightweight, so useful for making items that require good physical strength, as well as things like packaging which need to be able to support the contents correctly, (c) relatively low cost (especially overall, when ease of fabrication is taken into account.
(2)The "use" of plastics is not harmful per se, and plastics themselves are innocuous (one reason that they fail to readily biodegrade is that they do not interact with biological systems). But poor manangement of waste plastic can lead to problems.
(3)Failing to recycle and reuse synthetic polymers can lead to those items not landfilled (which is a separate issue - ultimately we would run out of landfill sites) items ending up in the sea, rivers or in the general environment where they can be hazardous to wildlife, and look unsightly.
But that is down to poor management, and societal attitudes, not down to the fact that the items are made of plastics.
(4)If we failed to manage sewage and simply discharged that into the streets or into rivers that would be a major problem too. But that doesn't mean we should "ban sewage" - just manage it in an effective way.
Answer:
0.84ppm
Explanation:
Mass of solute = 3.8 x 10⁻⁴g
Mass of solution = 450g
Unknown is the concentration in ppm; parts per million
The parts per million is one of the units of representing small concentration of solutes in a solution.
Solutes are the substances dissolving in another to give solution.
Here the concentration is expressed in a million units.
Concentration in ppm =
x 10⁶
=
x 10⁶
= 0.84ppm
<span>Coefficients in the reaction show numbers of moles in with substances are react or form.
2Kl(aq)+Cl2(g) ----> 2KCl (aq) + l2(g)
2 mol 1 mol 2 mol 1 mol
If we look at the reaction we can see that from 2 mol KI and 1 mol Cl2, form 2 mol KCl and 1 mol I2.</span>
Answer:
1.0 M is the concentration of hydrochloric acid.
Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:


1.0 M is the concentration of hydrochloric acid.