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Andrej [43]
3 years ago
8

6.Which set of coefficients correctly balances the following chemical equation?___ Mg(OH)2 + ___ HCl Imported Asset ___ MgCl2 +

___ H2O
A. 1, 1, 1, 1
B. 1, 2, 1, 2
C. 1, 2, 2, 2
D. 2, 4, 2, 4
Chemistry
2 answers:
scoundrel [369]3 years ago
6 0
Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O

B. 1, 2, 1, 2 
iVinArrow [24]3 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

A chemical reaction that contains same number of atoms on both reactant and product side is known as a balanced chemical equation.

For example, Mg(OH)_{2} + HCl \rightarrow MgCl_{2} + H_{2}O

Number of atoms on reactant side are as follows.

Mg = 1

O = 2

H = 3

Cl = 1

Number of atoms on product side are as follows.

Mg = 1

O = 1

H = 2

Cl = 2

Therefore, to balance this chemical equation we multiply HCl by 2 on reactant side and multiply H_{2}O by 2 on product side.

Hence, we can conclude that the balanced chemical equation will be as follows.

             Mg(OH)_{2} + 2HCl \rightarrow MgCl_{2} + 2H_{2}O

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56. What would be the valence electrons of 14Si, 16S, 32Ge respectively?
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Answer: D. 4,6,4

Explanation:

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For the following element, the valence electron can be noticed when we write the electronic configuration of each element.

Silicon =  1s2 2s2 2P6 3s2 3p2

Sulphur = 1s2 2s2 2P6 3s2 3p4

Germanium =  1s2 2s2 2P6 3s2 3p6 3d10 4s2 4p2

8 0
3 years ago
A liquid has a density of 1.17 g/cm3, how many liters of the liquid have a mass of 3.75 kg
Luda [366]
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5 0
3 years ago
5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------&gt; 1 Mg3(
professor190 [17]

Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

Hope this Helps!!!

5 0
3 years ago
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olganol [36]

Answer:

It should be 115.5 amu but you didnt type that as an answer choice so...

Explanation:

Bruh all you had to do was add oxygen and sulfur and subtract from the total to get your answer :D.

5 0
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