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Gre4nikov [31]
3 years ago
6

Applying Properties of Exponents In Exercise, use the properties of exponents to simplify the expression.

Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer: (a) e^3

(b) e^{10}

(c) \dfrac{1}{e^4}

(d) e^{4}

Step-by-step explanation:

Properties of exponents :

1) a^m\times a^n=a^{m+n}

2) \dfrac{a^m}{a^n}=a^{m-n}

3) (a^m)^n=a^{mn}

4) a^{-n}=\dfrac{1}{a^n}

Now , we simplify the given expression using the above properties.

a) (e^6)(e^{-3})

=e^{6+(-3)}   [By property (1)]

=e^{6-3}=e^3  [∵ (+)(-)=(-)]

b) (e^{-2})^{-5}

=e^{-2\times-5}  [By property (3)]

=e^{10}   [∵ (-)(-)=(+)]

c) (\dfrac{e^6}{e^2})^{-1}

=(e^{6-2})^{-1}    [By property (2)]

=(e^{4})^{-1}  

=\dfrac{1}{e^4}       [By property (4)]

d) (e^3)^{\frac{4}{3}}

=e^{3\times\frac{4}{3}}        [By property (3)]

=e^{4}  

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3x - 3y = -3<br>2x - y = -5​
Korolek [52]

For this case we must solve the following system of equations:

3x-3y = -3\\2x-y = -5

To solve we follow the steps below:

We multiply the second equation by -3:

-6x + 3y = 15

Thus, we have the equivalent system:

3x-3y = -3\\-6x + 3y = 15

We add the equations:

3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4

We look for the value of the variable "y":

2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3

Thus, the solution of the system is given by:

(x, y): (- 4, -3)

Answer:

(x, y): (- 4, -3)

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3 years ago
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Zina [86]

Answer:

y = 5

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Step-by-step explanation:

-4(2y) + 11y

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/ 3 /3

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3 0
2 years ago
Two groups went bowling. Here are the scores from each group.
vladimir2022 [97]

Answer:

Group A has greater variability

Step-by-step explanation:

Group A: 80, 100, 190, 110, 70, 90, 130

The variability of group A data :

Taking the range :

Maximum  = 190 ; Minimum = 70

Range = Maximum - Minimum ; 190 - 70 = 120

Group B : 50, 110, 100, 120, 107, 140, 150

The variability of group B data :

Taking the range :

Maximum  = 150 ; Minimum = 50

Range = Maximum - Minimum ; 150 - 50 = 100

Hence, Group A has greater variability

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