5^3 Sartre 10 + 4^3 sqrt 10
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
Answer:
1 container and 14 cups
Step-by-step explanation:
We know that 1 quart = 4 cups
therefore, 12 quart = 48 cups
each container has 34 cups
so one container would be full and remaining 48-34 =14 cups can be filled in another container.
Answer:
16 m × 11 m
Step-by-step explanation:
The dimension of the gym is 20 m x 15 m. An outbound of 2m width is to be cut out from the gym to form the basketball court.
The original length of gym = 20 m and original width of gym = 15 m
2 m would be cut at both sides of the gym length for the outbound. Also 2 m would be cut at both sides of the gym width for the outbound. Therefore:
Length of basketball court = 20 m - (2 * 2m) = 20 m - 4 m = 16 m
Width of basketball court = 15 m - (2 * 2m) = 15 m - 4 m = 11 m
Therefore the dimensions of the basketball court is:
16 m × 11 m
