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Vinil7 [7]
3 years ago
5

In the diagram below, triangle abc ~ triangle dec . What is the value of x? A. 28 b. 24 c. 22 d. 26

Mathematics
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

Option A.

Step-by-step explanation:

From the figure attached,

Given : ΔABC ~ ΔDEC

By the property of similarity,

"Corresponding sides of the similar triangles are proportional"

\frac{\text{AB}}{ED}=\frac{BC}{EC}=\frac{AC}{DC}

Since, \frac{\text{AB}}{ED}=\frac{AC}{DC}

\frac{42}{6}=\frac{x}{(32-x)}

6x = 42(32 - x)

6x = 1344 - 42x

6x + 42x = 1344

48x = 1344

x = \frac{1344}{48}

x = 28 units

Therefore, Option (A). x = 28 units will be the answer.

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slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

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Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

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8 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points (1, -7) and (-4, 8)?
melomori [17]
<h2>Answer:    y + 7  =  -3 (x - 1)</h2>

Step-by-step explanation:

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                                         =    - 15  ÷  5

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We can now use the point-slope form to write the equation for this line:

        y - y₁ = m(x - x₁) where (x₁ , y₁) = (1, -7)

             y - (-7) =  -3 ( x  -  1)

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3 years ago
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