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3 years ago

The width rectangle is 43 centimeters The perimeter is at least 198 cm let the length of the rectangle be /.

Mathematics

1 answer:

AnnyKZ [126]3 years ago

4 0

Answer:

198/43

Step-by-step explanation:

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120 -5 Integer hellp me

lord [1]

Answer: 115 is the answer

Step-by-step explanation:

7 0

3 years ago

On the number line below, length AB= {?}

SVEN [57.7K]

Answer:

29 units

Step-by-step explanation:

The length of a segment of a number line is the difference of the coordinates of the end points:

45 -16 = 29

3 0

3 years ago

Help me please i dont understand

matrenka [14]

Answer:

Step-by-step explanation:

The line where it says 2cm, extend that line to the top. You know have 2 triangles, call the one on the left A and the one on the right B

area of recntangle = bh

Rect A:

b = 5

h = 4 - 2

h = 2

bh = 5 x 2

bh = 10

Rect B:

b = 3

h = 4

bh = 4 X 3

bh = 12

Total = 10 + 12

Total = 22

5 0

1 year ago

Help? Please. Thanks???

Naya [18.7K]

The height is represented by d.

d = 10 feet

$10 = - 16 {t}^{2} - 7t + 61 \\ 0 = - 16 {t}^{2} - 7t + 51$

Use quadratic formula:

t = 1.58, -2.02 (reject)

1.58 seconds

3 0

3 years ago

Find the oth term of the geometric sequence 7, 14, 28, ...

yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

$a_n=a_1\cdot r^{n-1}$

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

$\frac{14}{7}=2,\:\quad \frac{28}{14}=2$

The ratio of all the adjacent terms is the same and equal to

$r=2$

now substituting r = 2 and a₁ = 7 in the nth term

$a_n=a_1\cdot r^{n-1}$

$a_n=7\cdot \:2^{n-1}$

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

6 0

3 years ago