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o-na [289]
4 years ago
8

| 215) 52.245 Please help

Mathematics
1 answer:
Virty [35]4 years ago
8 0

Answer: 11232.675

Step-by-step explanation:

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(-7-5)/(4-2)
-12/2= -6
7 0
3 years ago
In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o
ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = \frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}

X = 0.13

s = \sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for t_{6,0.005} is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = t_{6,0.005} . \frac{s}{\sqrt{N} }

E = 3.707. \frac{0.029}{\sqrt{7} }

E = 0.041

The interval will be:  

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0
4 years ago
10. The sum of two numbers is 102. One number is three less than twice the other.
netineya [11]

Answer:

(2n -3) + n = 102

2n - 3 + n = 102

3n - 3 = 102

3n = 105

n = 35 (the first number)

SO...

The other number is (2 x 35) - 3 =

                                           70 - 3 = 67 (the second number)

The numbers are 35 and 67.

35 + 67 = 102 CHECK!

7 0
3 years ago
Which quadrilaterals are also parallelograms?
sveticcg [70]
A, B, and D. A trapezoid cannot be parallel because the 2 left and right sides will eventually meet/connect. 
4 0
3 years ago
Find (F/g)(x)<br> F(x) = sqrt x^2-1<br> g(x) sqrt x-1
Margaret [11]

Answer:

Option A. √(x + 1)

Step-by-step explanation:

Data obtained from the question include:

f(x) = √(x² – 1)

g(x) = √(x – 1)

(f/g) (x) =..?

(x² – 1) => difference of two square

(x² – 1) => (x – 1)(x + 1)

f(x) = √(x² – 1)

f(x) = √(x – 1)(x + 1)

(f/g) (x) = f(x) /g(x)

f(x) = √(x – 1)(x + 1)

g(x) = √(x – 1)

(f/g) (x) = √(x – 1)(x + 1) / √(x – 1)

(f/g) (x) = √[(x – 1)(x + 1) / (x – 1)]

(f/g) (x) = √(x + 1)

7 0
4 years ago
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