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3 years ago

Need help with simplifying expressions

Mathematics

2 answers:

fgiga [73]3 years ago

6 0

The answer iss D.
..

Verizon [17]3 years ago

5 0

Answer:

D. 52a^2 + 26

Step-by-step explanation:

6( 4a^2 + 11a) - 13( 5a - 2) - a + 4( 7a^2 )

24a^2 + 66a - 65a + 26 - a + 28a^2

52a^2 + 26

hope this helps!

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Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0

3 years ago

Graph the inequality x > 3.

Marianna [84]

The graph would look like first one, or like this:

Hope this helped! c:

6 0

3 years ago

Read 2 more answers

Consider the line y= -7/4x+8

VARVARA [1.3K]

Perpendicular line has slope that multiplies to -1
paralel line has same slope

y=mx+b
slope=-7/4
perpendicular
4/7
(-7,-2)
-2=4/7(-7)+b
-2=-4+b
add 4 both sides
2=b
y=4/7x+2

paralel
y=-7/4x+b
-2=-7/4(-7)+b
-2=49/4+b
minus 49/4 from both sides (-2=-8/4)
-57/4=b
y=-7/4x-14.25

perpendicular
y=4/7x+2
paralel
y=-7/4x-14.25

8 0

2 years ago

A number between 49 and 95 that is a multiple of 4,5, and 10?

jek_recluse [69]

Answer: 60 and 80

Step-by-step explanation: Start off with the highest number, which is 10. The numbers between 49 and 95 that can be divided by 10 are 50, 60, 70, 80, and 90. Next, figure out what can be divided by 5. All of them can. Next, find out what numbers can be divided by 4. 50, 70, and 90 can’t because they would end up as a decimals. 60 and 80 can be divided by 4, 5, and 10.

5 0

3 years ago

MATH- Look at the picture and answer correctly so i can mark you as brainliest.

nadya68 [22]

Answer:

The answer in B please mark Brainliest.

Step-by-step explanation:

It is very easy.

5 0

2 years ago