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2 years ago

10

265,888 round to the nearest ten thousand

1 answer:

alexandr1967 [171]2 years ago

8 0

265,888 rounded to the nearest ten thousand is 70,000.

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Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago

Five tickets to a baseball game cost $60. how much do 2 tickets cost

bija089 [108]

Answer:

10

Step-by-step explanation:

60/5 = 12

12*2=24

2 tickets are $24

8 0

3 years ago

Read 2 more answers

I've literally asked this question 5 times lol. Can someone please help me?

Tju [1.3M]

I think i know the answer to that question. just wait for a sec.

6 0

2 years ago

Read 2 more answers

Compare the linear functions expressed below by data in a table and by an equation.

kondor19780726 [428]

Answer:

b,c,e

Step-by-step explanation:

7 0

2 years ago

Quadrilateral ABCD is reflected across the y-axis and translated 1 unit down to create quadrilateral EFGH .

sleet_krkn [62]

GH is parallel to FE

8 0

3 years ago