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Naily [24]
3 years ago
12

#20 can you help????

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0
The Answer is 136.11537 Fluid Ounces

In 1 Gallon there are 128 Fluid Ounces
In 1 cup there are 8.11537 Fluid Ounces
  So add them together and you get:   136.11537 Fluid Ounces
Ipatiy [6.2K]3 years ago
4 0
I think It might be 136 because 1c=8 oz and 1g=128 oz and adding that together is equal to 136
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The circumference of the circle is 9.42 inches, What is the diameter of the circle?
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EXPLANATION

Since the circumference of the circle is 9.42, we can get the diameter by applying the following relationship:

Circumference=2\pi r=2\pi\frac{d}{2}=\pi d

Isolating the diameter:

Diameter=\frac{Circumference}{\pi}

Plugging in the numbers:

Diameter=\frac{9.42}{3.14}=3

Therefore, the diameter is equal to 3 inches.

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Which statement describes the relationship between the intercepts of functions a and b?
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3 years ago
X and Y together complete a task in 4 days, Y and Z together in 5 days. If they work independently, who will finish the work in
pav-90 [236]

Answer:

c, Z

Step-by-step explanation:

x+y=4

<u>y+z=5</u>

y=4-x

4-x+z=5

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4 0
3 years ago
Each of 12 refrigerators of a certain type have been returned to a distributor because of the presence of a high pitched oscilla
Bond [772]

Answer:

a) P(X = 5) = 0.04397

b) The probability that X exceeds its mean by more than 1 standard deviation = P(z > 1) = 0.159

Step-by-step explanation:

a) This question can be solved using binomial distribution function formula

Using Binomial,

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of refrigerators to be examined before getting 5 refrigerators with defective compressors = 6

x = Number of successes required = 5

p = probability of success = probability of examining a refrigerator with defective compressor out of the total 12 = 5/12 = 0.4167

q = probability of failure = probability of examining a refrigerator without defective compressor out of the total 12 = 1 - (5/12) = 7/12 = 0.5833

P(X = 5) = ⁶C₅ (0.4167)⁵ (0.5833)⁶⁻⁵

P(X = 5) = ⁶C₅ (0.4167)⁵ (0.5833) = 1(0.01256)(0.5833) = 0.04397

P(X = 5) = 0.04397

b) The probability that X exceeds its mean by more than 1 standard deviation represents Z-score of z > 1

Using the normal distribution tables,

P(z > 1) = 1 - P(z ≤ 1) = 1 - 0.841 = 0.159

3 0
3 years ago
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