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3 years ago

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A college counselor wants to determine if the number of hours spent studying for a test can be used to predict the grades on a t

est. Identify the predictor variable and response variable.

2 answers:

Eva8 [605]3 years ago

8 0

Answer:

The predictor variable is the number of hours spent studying for a test.

The response variable is the grades on a test.

Step-by-step explanation:

Linear regression depicts the relationship between two variables by fitting a linear equation to experimental data values. One variable is known as an predictor (independent) variable, and the other is known as a response (dependent) variable.

The general form of a linear regression line is,

$\hat Y = a + bX$

Here,

<em>X</em> = predictor variable

Y = response variable.

The variable <em>b</em> = slope of the line, and <em>a</em> = intercept (the value of y when x = 0).

The main purpose of forming a regression line is to estimate or predict the value of the response variable for different values of the predictor variables.

The predictor variable is changes to observe the changes in the response variable.

In this case the college counselor wants to determine if the number of hours spent studying for a test can be used to predict the grades on a test.

The predictor variable is the number of hours spent studying for a test.

The response variable is the grades on a test.

Because the counselor is using the number of hours studied to estimate the marks obtained.

vfiekz [6]3 years ago

7 0

Answer:

Predictor variable = The number of hours spent studying for a test

Response variable = The grades on a test

Step-by-step explanation:

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Answer:

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3 years ago

A plane flying horizontally at an altitude of 1 mile and a speed of 510 mi/h passes directly over a radar station. Find the rate

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Answer:

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Step-by-step explanation:

Given

To properly solve this question, I illustrate some given parameters using attached image

From the image, apply Pythagoras theorem

$x^2 + 1^2 = y^2$

Differentiate w.r.t time (t)

$2x\frac{dx}{dt} + 0 = 2y\frac{dy}{dt}$

$2x\frac{dx}{dt} = 2y\frac{dy}{dt}$

Divide both sides by 2

$x\frac{dx}{dt} = y\frac{dy}{dt}$

From the question, we have that the plan travels are 510mi/h.

This implies that:

$\frac{dx}{dt} = 510mi/h$

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

$y = 2mi$

Apply Pythagoras theorem

$x^2 + 1^2 = y^2$

$x^2 + 1^2 = 2^2$

$x^2 + 1 = 4$

$x^2 = 4-1$

$x^2 = 3$

$x = \sqrt 3$

So, the expression becomes:

$x\frac{dx}{dt} = y\frac{dy}{dt}$

$\sqrt 3 * 510 = 2* \frac{dy}{dt}$

$\frac{\sqrt 3 * 510}{2} = \frac{dy}{dt}$

$\sqrt 3 * 255 = \frac{dy}{dt}$

$\frac{dy}{dt} = 255\sqrt 3$

$\frac{dy}{dt} = 255 * 1.7321$

$\frac{dy}{dt} = 441.655$

$\frac{dy}{dt} = 442$

<em>Hence, the distance is 442 miles</em>

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