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dybincka [34]
3 years ago
5

Trials in an experiment with a polygraph include 97 results that include 23 cases of wrong results and 74 cases of correct resul

ts. Use a 0.05 signifcance level to test the claim that such polygraph results are correct less than 80% of the time. Based on the results should polygraph test results be prohibited as evidence in trials? identify the null hypothesis, alternative hypothesis, test statistic, P-value conclusion about the null hypothesis and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution as an approximation of the binomial distribution
a. H0:p= 0.80 b. H0:p=0.20
H1:p>0.80 H1: p =/ 0.20
c. H0:p=0.20 d. H0:p= 0.80
H1:p< 0.20 H1: p< 0.80
e. H0: p= 0.20 f. H0: p= 0.80
H1: p>0.20 H1:p =/ 0.80
the test statistic is z=
the P-value is ?
Mathematics
1 answer:
o-na [289]3 years ago
8 0

Answer:

H0:p= 0.80                 H1: p< 0.80  one tailed test

Step-by-step explanation:

We state the null and alternative hypotheses as that the results are 80 % against the claim that the results are less than 80%.

H0:p= 0.80                 H1: p< 0.80  one tailed test

p2= 0.8 , p1= 74/97= 0.763

q1= 1-0.763= 0.237    q2= 0.2

The level of significance is 0.05 .

The Z∝= ±1.645 for ∝= 0.05

The test statistic used here is

Z= p1-p2/ √pq/n

Putting the values:

Z= 0.763 -0.8 / √ 0.8*0.2/97

z= -0.037/ 0.0406

z= -0.9113

The Z∝ = ±1.645 for ∝= 0.05 for one tailed test.

As the calculated value  does not fall in the critical region  we fail to reject the null hypothesis. There is not sufficient evidence to support  the claim that such polygraph results are correct less than 80% of the time.

Using the normal probability table.

P (Z <  -0.9113)= 1- P(z= 0.9311) = 1- 0.8238= 0.1762

If P- value is smaller than the significance level reject H0.

0.1762> 0.005  Fail to reject H0.

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Vaselesa [24]

Hello!

<u><em>Answer:  ⇒⇒⇒⇒⇒⇒⇒ =54</em></u>

_________________________________________________________________

Step-by-step explanation:

First you had to convert element to fraction.

\frac{2}{3}*\frac{81}{1}

Then you had to cross out by the common factor of 3.

\frac{2}{1}=\frac{27}{1}

Multiply by the fraction.

\frac{2*27}{1*1}

Multiply by the number.

2*27=54

=\frac{54}{1*1}

Again multiply by the number.

1*1=1

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Apply rule.

\frac{54}{1}=54

54 is the right answer.

______________________________________________________________

Hope this helps!

Thank you for posting your question at here on brainly.

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4 0
3 years ago
Amar keeps picking playing cards out of a standard deck of 52 cards in the hopes that he will
lapo4ka [179]

Answer:

The required probability is, 0.78

Step-by-step explanation:

There are, (52 - 13) = 39 cards which are not spade

5 cards can be chosen from the deck of 52 cards in

^{52}{C}_{5}  ways

and out of these 5 choices, none of them will be spade in,

^{39}{C}_{5}  ways

So,

P(None of the chosen cards is spade)

= \frac {^{39}{C}_{5}}{^{52}{C}_{5}}

\simeq 0.22

Hence,

P(out of these 5 choices, at least one card is spade)

\simeq (1 - 0.22)

= 0.78

4 0
3 years ago
Please help! Correct Answers only!
mafiozo [28]

Answer:

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Step-by-step explanation:

Using the given formula :

I = P × R × T

I = 40000 × 15/100 × 2

I = $12000

5 0
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If you flip three fair coins, what is the probability that the first two flips will both be heads, and the third flip will be ei
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Answer:

1/4

Step-by-step explanation:

This is correct on khan academy!

6 0
3 years ago
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Answer:

D or y-25=2(x-10)

Step-by-step explanation:

If you graph all or the answers the only one that hits both points is D.

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