I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The 
terms cancel, leaving you with
and the limand is continuous at 
, so we can substitute it to find the limit has a value of -1/18.
Answer:
$11.13
Step-by-step explanation:
$7.00 + $3.50 = $10.50
6% of $10.50 is $0.63
$10.50 + 0.63 = $11.13
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
f(x) = √3x
g(x) = √48x
(f . g)(x) = ?
Step 02:
(f . g)(x) :
![\text{ (f.g)(x) = }\sqrt[]{3(\sqrt[]{48x)}}](https://tex.z-dn.net/?f=%5Ctext%7B%20%20%20%20%20%20%20%20%20%20%28f.g%29%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B3%28%5Csqrt%5B%5D%7B48x%29%7D%7D)
![(f.g)(x)\text{ = }\sqrt[]{3(48x)^{\frac{1}{2}}}\text{ }](https://tex.z-dn.net/?f=%28f.g%29%28x%29%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B3%2848x%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%5Ctext%7B%20%7D)
(f.g)(x) = 12 √ x
The answer is:
(f.g)(x) = 12 √ x
