Answer:
685.6 J
Explanation:
The latent heat of vaporization of ammonia is
L = 1371.2 kJ/kg
mass of ammonia, m = 0.0005 Kg
Heat = mass x latent heat of vaporization
H = 0.0005 x 1371.2
H = 0.686 kJ
H = 685.6 J
Thus, the amount of heat required to vaporize the ammonia is 685.6 J.
Answer:
Correct answer: Ep₁ = 105.11 J
Explanation:
if we take as the zero reference point the bottom of the hole then the height difference is 11 m. Let named h₁ = 11 m
The formula for calculating potential energy is:
E p = m g h => mg · 9.0 m = 86 J => mg = 86/9
when we substitute this into the next formula we get
m g h₁ = 86/9 · 11 = 105.11 J
God is with you!!!
Answer:
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Explanation:
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I believe the answer might be lower resistance. (My apologies if it's not!)
~Hope this helped!