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defon
4 years ago
7

Which part of the electromagnetic spectrum would be most helpful to enable a doctor to identify a broken bone?

Physics
2 answers:
Anna [14]4 years ago
4 0
The correct answer of the given question above would be X-RAYS. The part of the electromagnetic spectrum that would be most helpful to enable a doctor to identify a broken bone is the use of X-rays. An x-ray is an electromagnetic wave that is able to pass through materials opaque to light. Hope this answer helps. Thanks for posting your question.
son4ous [18]4 years ago
3 0

Answer:

<u><em>The answer is</em></u>: <u>X-rays.</u>

Explanation:

<em>Doctors ask for</em> x-rays <em>if they think a bone may be broken. </em>

An x-ray is a quick and painless test that generates images of the internal structures of the body, especially the bones.<em> </em>X-ray<em> beams pass through the body and are absorbed in different amounts depending on the density of the material through which they pass. </em>

<u><em>The answer is</em></u>: <u>X-rays.</u>

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The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su
balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

\rm  I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2  \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2}  \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days

Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ1

8 0
2 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 19 cm apart. The sound
Roman55 [17]

Answer:

a.96cm

b.77cm

Explanation:

Highest intensity,d_1=19cm

Lowest intensity,d_2=29cm

d_1+d_2=19+29=48cm  

48cm is the distance for half-wave, wavelength =48cm*2=96cm

b. From a, above we know that half-wavelength is 48cm

Also, the distance of known  maximum is 29cm

Next maximum is calculated as:

Next \m\aximum=Last \ Maximum+ \ 0.5Wavelength\\=29cm+48cm\\=77cm

The next maximum will occur at 77cm

6 0
4 years ago
Please give me the answer of this question ​
Zolol [24]
Da answer to your question is is is is is is is is is is is is

C
8 0
3 years ago
Determine the diameter of the largest circular hole that can be punched into a sheet of polystyrene 6 mm thick, knowing that the
Yakvenalex [24]

Answer:

43.41 mm

Explanation:

Given:

thickness of sheet, t = 6 mm

Force exerted by punch, F = 45 KN

Average shearing stress, T = 55 MPa

From average shearing stress T = Force F / Area A

Hence area = force/stress =45000/ 55 =818.18 mm^2

From area = pi*diameter*thickness

diameter = area/(pi* thickness)

= 818.18/(3.142*6)

= 43.41 mm

4 0
3 years ago
Object A of mass M is moving east at speed v. It collides with object B of mass 2M that was initially at rest. The motion of the
Firlakuza [10]

Answer:

v_B=\frac{v}{3}

Explanation:

Given that:

mass of object A, m_A=M

mass of object B, m_B=2M

speed of object A, v_A=v

So, according to the conservation of momentum, the momentum before collision is equal to the momentum after conservation.

m_A.v+m_B\times 0=m_A\times v_A +m_B\times v_B

M\times v+0 = M\times \frac{v}{3}+2M\times v_B

2M\times v_B= \frac{2M\times v}{3}

v_B=\frac{v}{3}

3 0
3 years ago
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