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lisabon 2012 [21]
3 years ago
14

A binary star system consists of two stars of masses m1 and m2. The stars, which gravitationally attract each other, revolve aro

und the center of mass of the system. The star with mass m1 has a centripetal acceleration of magnitude a1. Note that you do not need to understand universal gravitation to solve this problem.
Physics
1 answer:
mote1985 [20]3 years ago
8 0

Answer: a_{2}=\frac{m_{1}}{m_{2}} a_{1}

Explanation:

The rest of the question is below:

Find a2, the magnitude of the centripetal acceleration of the star with mass m2.

Assuming both stars are describing a uniform circular motion, their acceleration vector is directed towards the center of mass of the system (that's why it's called centripetal acceleration).  

Now, according to Newton's 2nd law, the force F is directly proportional and in the same direction as the acceleration.

For m_{1}:

F_{1}=m_{1}a_{1}  

For m_{2}:

F_{2}=m_{2}a_{2}  

If the centripetal force is the same for both stars:

F_{1}=F_{2}  

m_{1}a_{1}=m_{2}a_{2}  

Isolating a_{2}:

a_{2}=\frac{m_{1}}{m_{2}} a_{1}

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The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is
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Answer:

\frac{T_t}{T_c} = 1.32

Explanation:

The torque applied on an object can be calculated by the following formula:

T = Fr

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For car wheel:

T_c = Fr_c\\

For truck wheel:

T_t = Fr_t

Dividing both:

\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}

for the same force applied on both wheels:

\frac{T_t}{T_c} = \frac{r_t}{r_c} \\

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\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\

\frac{T_t}{T_c} = 1.32

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