It also detects if you are right or wrong
2 answers:
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Answer:
The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 21.6 - 0.3 = $21.3.
The upper end of the interval is the sample mean added to M. So it is 21.6 + 0.3 = $21.9.
The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.
Answer:
Claim is true that most medical malpractice lawsuits are dropped or dismissed.
Step-by-step explanation:
Given :In a study of 799 randomly selected medical malpractice lawsuits, it was found that 499 of them were dropped or dismissed.
To Find : Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed.
Solution:
n = 799
x = 499
We will use one sample proportion test
We are given that the claim is most medical malpractice lawsuits are dropped or dismissed.
Probability of dropped or dismissed is 1/2
Formula of test statistic =
=
= 7.038
p value (z>7.038) is 0
α =0.05
So, p value < α
So, we reject the null hypothesis
So,claim is true
Hence most medical malpractice lawsuits are dropped or dismissed.