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notka56 [123]
3 years ago
11

Use the digits 4,5 and 6 to write a number in which 4 has a value of 400. Explain your thinking.

Mathematics
1 answer:
andre [41]3 years ago
7 0
456 or 465. Each one has 4 in the hundreds place.
5)  920,438    .. I took 1000 from 921,438.
6)  175,000      . I added a one in the hundred thousands place
7)  7500 hundreds + 0 tens + 2 ones
     7500 tens + 2 ones
     7,502 ones
8)  15600 hundreds + 30 tens + 8 ones
     15630 tens + 8 ones
     15638 ones
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Answer:

Step-by-step explanation:

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Construct three parallel lines. Then construct two arbitrary non parallel transversal of the parallel lines. Make sure that the
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The image lines constructed are called parallel lines. They are parallel because  they are all equidistant to each other at every point and at no point between any of the lines will there be an intersection of the three lines.

<h3>What does it mean for two or more lines to be equidistant from each other?</h3>

Equidistance is simply another word for equal in distance. That is, parallel lines maintain equal distance from each other at all points along them.

See the attached construction as well as more insights about parallel lines from the link below.

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1 year ago
Three hens can lay 3 eggs in 3 days.In how many days can 7 hens lay 7 eggs?
Anna71 [15]

Answer: 3 days


Step-by-step explanation: It would take 3 days for seven hens to 7 lay eggs because each hen lays an egg each day.

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What is 3.25% written as a fraction in lowest terms?
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A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
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