Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Bill paints 1/2 per hour. Bob paints 1/3 per hour. 1/2x+1/3x=1
Answer:
X=2
Step-by-step explanation:
Using distributive property: 1/3(12x-24)=16
4x- 8=16
Using oposite oporations on both sides:
4x-8=16
4x+8=16-8
4x=8
8/4=2
x=2
can I have brainliest please
Answer:
the answer is that he would have to win 7 games in a row to get 75%
Step-by-step explanation:
the correct answer will be c.